json - 如何在不定义内部模板的情况下使用Grails JSON View ？

Question

我有一个域类:

class Business {
    String name
    String description
}

我有以下JSON模板:
index.gson:为对象列表生成JSON
_business.gson:为业务对象生成JSON

index.gson

import server.Business
model {
    Iterable businessList
}
json {
    result tmpl.business(businessList ?: [])
}

_business.gson

model {
        Business business
}
json {
    id business.id
    name business.name
} 

如何不使用_business.gson模板即可为业务对象生成JSON？

我想采用一种仅拥有index.gson并手动呈现内部对象的方法。

import server.Business
model {
    Iterable businessList
}

json {
    **WHAT SHOULD I ADD HERE?**
}

json(businessList.toList()) {
    **I also noticed that I can use this syntax, BUT WHAT SHOULD I ADD HERE?**
}

Answer 1

您可以在json闭包内做任何您想做的事情。

json(businessList.toList()) { Business business ->
    id business.id
    name business.name
    description business.description
}