spring-boot - Spring Boot Apache CXF JAX-RS 服务上下文路径/基本 URI

Question

我像这样在 Spring Boot 中配置我的 JAXRS 服务器:

    JAXRSServerFactoryBean factoryBean = new JAXRSServerFactoryBean();
    factoryBean.setBus(this.bus);
    factoryBean.setFeatures(singletonList(swagger2Feature()));
    factoryBean.setServiceBeans(Arrays.asList(blah(), blah2(), blah3()));
    factoryBean.setAddress("/api/v1/"); // HERE

    List<Object> providers = new ArrayList<>();
    providers.add(new JacksonJaxbJsonProvider());
    factoryBean.setProviders(providers);

    BindingFactoryManager manager = factoryBean.getBus().getExtension(BindingFactoryManager.class);
    JAXRSBindingFactory restFactory = new JAXRSBindingFactory();
    restFactory.setBus(factoryBean.getBus());
    manager.registerBindingFactory(JAXRSBindingFactory.JAXRS_BINDING_ID, restFactory);

    return factoryBean.create();

但是，URL 前面总是需要 /services，这很麻烦(但不是世界末日)。有什么方法可以删除 /services 并将其部署到根上下文吗？

Answer 1

如果您还没有创建自己的 CxfServlet bean，您可以通过在 application.properties 文件中设置 cxf.path 属性来设置路径

cxf.path=/

另一种方法是覆盖ServletRegistrationBean。

@Bean
public ServletRegistrationBean cxfServletRegistration() {
    String urlMapping = "/*";
    ServletRegistrationBean registration = new ServletRegistrationBean(
            new CXFServlet(), urlMapping);
    registration.setLoadOnStartup(-1);
    return registration;
}