grails - 具有命名参数的findAll异常

Question

我正在尝试执行类似于grails示例之一的findAll。这就是我所拥有的:

def beverage = Beverage.findAll("from Beverage as b where b.id in (:ids)",[ids: [1,2]])

我得到:

java.lang.Integer cannot be cast to java.lang.Long

Answer 1

您只需要将硬编码的id强制转换为longs:

[ids: [1L, 2L]]