javascript - 如何找到 JSONArray 中两个连续对象之间的最大和最小差异

Question

我有一个 JSON 数据，例如

{
    "data": [{
        "distance": "700",
        "name": "xyz"
    }, {
        "distance": "680",
        "name": "abc"
    }, {
        "distance": "670",
        "name": "lmn"
    }, {
        "distance": "620",
        "name": "pqr"
    }, {
        "distance": "400",
        "name": "tuv"
    }]
}

我想找到两个连续节点之间的最大和最小距离。我尝试了以下代码，但我不知道我错过了什么这里我尝试使用jQuery排序来实现它。

var min = data[0].distance - data[1].distance,
    max = data[0].distance - data[1].distance;
data.sort(function (a, b) {
    var temp = a.distance - b.distance;
    if (temp > max)
        max = temp;
    if (temp < min)
        min = temp;
});

我什至尝试使用普通的 jQuery forEach 循环

var min = data[0].distance - data[1].distance,
    max = data[0].distance - data[1].distance;
data.forEach(function (d, i) {
    var temp = data[i + 1].distance - d.distance;
    if (temp > max)
        max = temp;
    if (temp < min)
        min = temp;
});

Answer 1

你可以这样做:

// Set default values to the max and min, to compare them later
var min = Number.MAX_VALUE,
    max = Number.MIN_VALUE;

// Iterate over the data object
for (var i = obj.data.length - 2; i >= 0; i--) {
    // Get the absolute(ignoring negatives) difference
    var temp = Math.abs(obj.data[i].distance - obj.data[i + 1].distance);

    // update values accordingly
    min = Math.min(min, temp);
    max = Math.max(max, temp);
}
console.log(min, max);

var obj = {
    "data": [{
        "distance": "700",
        "name": "xyz"
    }, {
        "distance": "680",
        "name": "abc"
    }, {
        "distance": "670",
        "name": "lmn"
    }, {
        "distance": "620",
        "name": "pqr"
    }, {
        "distance": "400",
        "name": "tuv"
    }]
};

var min = Number.MAX_VALUE,
    max = Number.MIN_VALUE;
for (var i = obj.data.length - 2; i >= 0; i--) {
    var temp = Math.abs(obj.data[i].distance - obj.data[i + 1].distance);
    min = Math.min(min, temp);
    max = Math.max(max, temp);
}
console.log(min, max);