grails - groovy:将字符串(列表)转换为Groovy列表

Question

import groovy.json.JsonSlurper

def ver = "['a', 'b', 'c']"
def jsonSlurper = new JsonSlurper()
def ver_list = jsonSlurper.parseText(ver)
println ver_list

这就是我在做什么。我想遍历 ver_list。而且似乎很难找到解决方案。

当我打印ver_list时，这是错误:

Caught: groovy.json.JsonException: Unable to determine the current character, it is not a string, number, array, or object

The current character read is ''' with an int value of 39
Unable to determine the current character, it is not a string, number, array, or object
line number 1
index number 1
['a', 'b', 'c']
.^
groovy.json.JsonException: Unable to determine the current character, it is not a string, number, array, or object

The current character read is ''' with an int value of 39
Unable to determine the current character, it is not a string, number, array, or object
line number 1
index number 1
['a', 'b', 'c']

Answer 1

有效的json字符串必须用双引号引起来。

因此更改此行中的代码即可使用:

def ver = '["a", "b", "c"]'

但是，如果您需要解析无效的json，则可以尝试LAX解析器。

那么甚至可以解析以下字符串

import groovy.json.JsonSlurper
import groovy.json.JsonParserType

def ver = "[a, 'b', 001]"
def jsonSlurper = new JsonSlurper().setType( JsonParserType.LAX )
def ver_list = jsonSlurper.parseText(ver)
println ver_list