javascript - 将 for 循环和 while 循环转换为 do...while 循环 JavaScript

Question

我有这 2 个循环来查找整数数组中的最大数字(一个 for 循环和一个 while 循环具有相同的目的)对于:

var forHighest = function(array) {
  var highest = array[0];
  for (var i = 0; i < array.length; i++) {
    if (highest < array[i]) {
      highest = array[i];
    }
  }
  return highest;
};

同时:

var whileHighest = function(array) {
  var i = 0;
  var highest = array[0];
  while (i < array.length) {
    if (array[i] > highest)
      highest = array[i];
    i++;
  }
  return highest;
};

但现在我需要创建一个 While 循环，但我尝试的所有操作都会不断给出数组 [0] 索引处的数字。我认为我以前从未在功能上使用过 do...while 循环，所以也许我没有完全理解它们是如何工作的。以下是我的一些尝试:

var doWhile = function(array) {
  var i = 0;
  do {
    i++;
  } while (i < array.length);
  if (array[i] > highest)
    highest = array[i];
  return highest;
};

还有:

var i = 0;
var highest = array[0];
do{
    if(highest < array[i]){
    highest = array[i];
    i++;
    } 
  } while(i < array.length);

和:

var doWhile = function(array) {
    var i = [i];
//  var i = 0;
    var highest = array[i];
    do
      {
       i++;
      } while (array[i] < highest && i < array.length);
        //  if (array[i] > highest);
        return array[i];

但是它们都不起作用。有人可以向我解释我做错了什么吗？

Answer 1

As mentioned in the comments, there are better ways to get the max/min in an array, but the point of the question is to know how write a do...while loop

你的第二次做... while 很接近

var i = 0;
var highest = array[0];
do {
    if (highest < array[i]){
        highest = array[i];
    }
    i++;  // this line moved out of the if block
} while(i < array.length);

但是，更正确的是

var i = 1;
var highest = array[0];
if (array.length > 1) {
    do {
        if(highest < array[i]){
            highest = array[i];
        }
        i++;  
    } while(i < array.length);
}

因为不需要检查数组是否是单个元素，也不需要检查 array[0] 和 array[0]，所以可以用 i = 1 开始循环