Javascript 和 Regex 将时间存储在数组中

Question

我想用正则表达式将时间存储在数组中。这是我正在使用的:

var re = /\b\d{1,2}:\d{2}\b/g; 
var txt =  '9:50 This is a test with end time in the Clammr 10:10';
var str = txt;
var m;               
while ((m = re.exec(str)) !== null) {
    if (m.index === re.lastIndex) {
        re.lastIndex++;
    }                   
var starttime = m[0];
var endtime = m[1];
}               
var text = txt.replace(starttime, '');
text = text.replace(endtime, '');
text = jQuery.trim(text);   
console.log('[shortcode text="'+ text +'" start="' + starttime + '" end="' + endtime + '"]');

我希望最后得到这个结果:

[shortcode text="This is an awesome Clammr" start="9:50" end=10:10"]

但不知道如何，但我得到了这个:

[shortcode text="9:50 This is a test with end time in the Clammr" start="10:10" end="undefined"]

Answer 1

Exec 返回 [match,index,string] ，因此为了获得匹配，只需使用第一个索引 m[0] :

检查这个片段。

var re = /\b\d{1,2}:\d{2}\b/g; 
var txt =  '9:50 This is a test with end time in the Clammr 10:10';
var str = txt;
var m;           
var times = [];    
while ((m = re.exec(str)) !== null) {
 times.push(m[0]);
}               
var text = txt.replace(times[0], '');
text = text.replace(times[1], '');
text = jQuery.trim(text); 

  
$('body').append('[shortcode text="'+ text +'" start="' + times[0] + '" end="' + times[1] + '"]');

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>