java - 为什么调用空 Atomic 类的方法不会产生异常？

Question

import java.util.concurrent.*;
import java.util.concurrent.atomic.AtomicInteger;

public class _7_Synchronizing_Data_Access {
    private AtomicInteger count;

    private void incrementAndReport() {
        System.out.print(count.incrementAndGet() + "here"); //does not print
    }

    public static void main(String[] args) {
        ExecutorService service = null;
        try {
            service = Executors.newFixedThreadPool(20);
            _7_Synchronizing_Data_Access manager = new _7_Synchronizing_Data_Access();
            for (int i = 0; i < 10; i++)
                service.submit(() -> manager.incrementAndReport());
        } finally {
            if (service != null)
                service.shutdown();
        }
    }
}

运行这个程序什么都不输出。甚至没有 NullPointerException。如您所见，我没有实例化 count。我希望它会引发错误。这是为什么？

Answer 1

NullPointerException异常被抛出并被捕获，但为了看到它们，你需要检查 Future service.submit 返回的实例调用:

按如下方式更改循环:

for (int i = 0; i < 10; i++) {
    Future f = service.submit(() -> manager.incrementAndReport());
    try {
        System.out.println (f.get ());
    }
    catch (ExecutionException exex) {
        System.out.println (exex);
    }
    catch (InterruptedException intEx) {
        System.out.println (intEx);
    }
}

将输出:

java.util.concurrent.ExecutionException: java.lang.NullPointerException
java.util.concurrent.ExecutionException: java.lang.NullPointerException
java.util.concurrent.ExecutionException: java.lang.NullPointerException
java.util.concurrent.ExecutionException: java.lang.NullPointerException
java.util.concurrent.ExecutionException: java.lang.NullPointerException
java.util.concurrent.ExecutionException: java.lang.NullPointerException
java.util.concurrent.ExecutionException: java.lang.NullPointerException
java.util.concurrent.ExecutionException: java.lang.NullPointerException
java.util.concurrent.ExecutionException: java.lang.NullPointerException
java.util.concurrent.ExecutionException: java.lang.NullPointerException

如果将 System.out.println(count.incrementAndGet() + "here"); 括起来，您还会看到会抛出异常。带有 try-catch 的语句:

private void incrementAndReport() {
    try {
        System.out.println(count.incrementAndGet() + "here"); //does not print
    }
    catch (Exception exc) {
        System.out.println (exc);
    }
}