javascript - 命名函数(而不是匿名)和创建对它的引用有什么区别？

Question

在我发起的另一个帖子的评论中，有人这样说:

@adlwalrus yes. try this: var foo = function bar(){}; console.log(foo); But be aware that bar is only function name (what does it mean I'm not sure exactly myself) and not a reference to it, so you can't call it by doing bar(). And assigning (even named function) is not the same as declaring a function. Hoisting (bumping to top of the scope) only works for declarations, assignment will stay in place. – valentinas 6 hours ago

如果无法使用 bar() 调用函数名称，它有什么作用？

Answer 1

让函数调用自身。

var x = function y(val){
            if (val){
                console.log(val);
                y(val-1);
            }
        }; 
x(5);
> 3  
> 2  
> 1 
y(3); 
> ReferenceError: y is not defined