javascript - 如何根据 JavaScript 中的其他数据值获取 JSON 数据

Question

我的Json是这样的:

[    
 {"isoCode":"BW","name":"Botswana ","CashOut":"Y","BankOut":"","MMT":null},
 {"isoCode":"BR","name":"Brazil ","CashOut":"Y","BankOut":"Y","MMT":null},
 {"isoCode":"BG","name":"Bulgaria ","CashOut":"Y","BankOut":"Y","MMT":"Y"},
 {"isoCode":"BF","name":"Burkina Faso","CashOut":"Y","BankOut":"","MMT":null},
 {"isoCode":"BI","name":"Burundi","CashOut":"","BankOut":"","MMT":"Y"},
 {"isoCode":"KH","name":"Cambodia","CashOut":"Y","BankOut":"","MMT":null}
]

我希望使用 JavaScript 将 BankOut 值为“Y”的所有名称放入数组中，以便在 Protractor 自动化中使用这些名称。

Answer 1

您需要使用数组的过滤方法。它以函数作为参数。并对数组的每个元素运行它。如果函数返回 true(或其他真值)，则该元素保留在新创建的数组中。

var list =[    {"isoCode":"BW","name":"Botswana ","CashOut":"Y","BankOut":"","MMT":null},
 {"isoCode":"BR","name":"Brazil ","CashOut":"Y","BankOut":"Y","MMT":null},
 {"isoCode":"BG","name":"Bulgaria ","CashOut":"Y","BankOut":"Y","MMT":"Y"},
 {"isoCode":"BF","name":"Burkina Faso ",   "CashOut":"Y","BankOut":"","MMT":null},
 {"isoCode":"BI","name":"Burundi","CashOut":"","BankOut":"","MMT":"Y"},
 {"isoCode":"KH","name":"Cambodia","CashOut":"Y","BankOut":"","MMT":null}
 ];

var onlyBankOutY = list.filter(function (item) {
  return item.BankOut === 'Y';
});

document.body.innerHTML = onlyBankOutY.map(function (item) {
  return JSON.stringify(item);
}).join('<br>');