json - Grails GSON JSON View

Question

我想生成与此类似的JSON输出:

var json = {
        id: "1",
        name: "AAA",
        children: [{
            id: "2",
            name: "BBB",
            data: {
                relation: "<b>Connections:</b><ul><li> AAA <div>(relation: direct)</div></li><li> CCC <div>(relation: direct)</div></li></ul>"
            },
            children: [{
                id: "3",
                name: "CCC",
                data: {
                    relation: "<b>Connections:</b><ul><li> BBB <div>(relation: direct)</div></li></ul>"
                },
                children: []
            }]
        }, ....

这是我到目前为止所做的:

grails create-domain-resource json.Object

class Object{
    String name
    String relation
    static hasMany = [children: Object]

    public String getData() {
        def writer = new StringWriter()

_object.gson

//json g.render(hero)
json {
    //data hero.data
    data: {relation hero.relation}
    name hero.name
}

问题
我无法产生:

 data: {
                    relation: "<b>Connections:</b><ul><li> BBB <div>(relation: direct)</div></li></ul>"
                },

问题:
1)我已经阅读了官方文档，但无法找到 transient 字段
2)什么是混合json和xml / html的最佳方法。
3)如何将json代码传递给另一个 View 变量

先感谢您

Answer 1

您可以在以下位置查看官方文档以获取gson View :

http://views.grails.org/latest/#_json_view_api

域类

class Object{
    String name
    String relation
    static hasMany = [children: Object]

    public String getRelation() {

模板1 object.gson

import json.Object

model {
    Object object
}

json tmpl.object(object)

模板2 _object.gson

import json.Object

model {
    Object object
}

json {
    id object.id
    data(relation: object.relation)
    name object.name
    children g.render(object.children,[ excludes:['exclude_fields']])
    //children g.render(object.children,[resolveTemplate: false]) // one to many relations - avoid circular error
    //object2 object.book.name // one to one relations
}

ObjectController

import grails.plugin.json.view.JsonViewTemplateEngine
import org.springframework.beans.factory.annotation.Autowired

    @Autowired
    JsonViewTemplateEngine templateEngine
    def test() {
        def t = templateEngine.resolveTemplate('/object/object')
        def writable = t.make(object: Object.get(params.id))
        def sw = new StringWriter()
        writable.writeTo( sw )
        return [json:sw]
    }

问题:

1)我已经阅读了官方文档，但无法找到过渡字段- ，您可以使用命名参数，这些参数是对象或 setter/getter 的有效值

2)什么是混合json和xml / html的最佳方法。 -**我想您可以检查: http://docs.groovy-lang.org/latest/html/gapi/groovy/json/StreamingJsonBuilder.html **

3)如何将json代码传递给另一个 View 变量-**在objectController处检查以上代码**