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javascript - Codeigniter 中的 JQuery Ajax POST 不起作用

转载 作者:行者123 更新时间:2023-12-02 14:23:39 24 4
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我在 codeigniter 中使用 jquery ajax post 时遇到问题,我遇到的问题是当单击提交按钮时,发生错误

404 not found

这是我的代码

home.js

form.on('submit', function(e){
e.preventDefault();
var fields = {};
form.find('input','textarea').each(function(index, el){
el.readOnly = true;
fields[$(el).attr('name')] = $(el).val();
});

// send request to server
$.ajax({
type: 'POST',
url: '/home/tryproduct/',
data: fields,
dataType: 'json'
})
.done(function(result){
if(result.error === false){
alert(result.message);
} else {
alert(result.message);
}
form.find('input','textarea').each(function(index, el){
el.readOnly = false;
});
form[0].reset();
});
});

这是我的观点

<form class="row" name="free-trial">
<div class="col-sm-6 col-xs-12">
<div class="form-group">
<button type="button" onclick="autoFillUsingLinkedin()" class="btn btn-linkedin btn-block">
<span class="icon icon-social-linkedin"></span>
Autofill Using LinkedIn
</button>
</div>
</div>
<div class="col-sm-6 col-xs-12"></div>
<div class="col-sm-6 col-xs-12">
<div class="form-group">
<label>Name</label>
<div class="row between-xs">
<input type="text"
name="firstName" placeholder="First Name" class="form-control col-xs" required=""/>
<?php echo form_error('firstName'); ?>
<input type="text" name="lastName" placeholder="Last Name" class="form-control col-xs" required=""/>
<?php echo form_error('lastName'); ?>
</div>
</div>
<div class="form-group">
<label>Company</label>
<input type="text" name="company" placeholder="Your Current Company" class="form-control" required=""/>
</div>
<div class="form-group">
<label>Position</label>
<input type="text" name="position" placeholder="Position On Your Company" class="form-control" required=""/>
</div>
<div class="form-group">
<label>Address</label>
<input type="text" name="address" placeholder="JL. Jalan 12. Kota. Bandung" class="form-control" required=""/>
</div>
</div>
<div class="col-sm-6 col-xs-12">
<div class="form-group">
<label>Email</label>
<input type="email" name="email" placeholder="We Will Use This For Registration" class="form-control" required=""/>
<?php echo form_error('email'); ?>
</div>
<div class="form-group">
<label>Phone Number</label>
<input type="text" name="phone" placeholder="+(62) xxx" class="form-control" required=""/>
</div>
<div class="form-group">
<label>Notes</label>
<textarea type="text" name="notes" placeholder="Tell Us What You Want" rows="4" class="form-control" required=""></textarea>
</div>
</div>
<div class="col-sm-6 col-xs-12">
<div class="form-group">
<button type="submit" class="btn btn-primary btn-block">
<span class="icon icon-paper-airplane"></span>
SUBMIT FOR FREE TRIAL
</button>
</div>
</div>
</form>

Controller

public function tryproduct(){
$this->view = FALSE;
if ($_SERVER['REQUEST_METHOD'] !== 'POST') return;
$data = array(
'firstname' => $this->input->post('firstname'),
'lastname' => $this->input->post('lastname'),
'position' => $this->input->post('position'),
'company' => $this->input->post('company'),
'address' => $this->input->post('address'),
'phone' => $this->input->post('phone'),
'email' => $this->input->post('email'),
'notes' => $this->input->post('notes')
);
$id = $this->trial_request->insert($data);
if(!$id){
echo json_encode(array(
'error' => true,
'message' => 'error register product trial'
));
} else {
echo json_encode(array(
'error' => false,
'message' => 'success register product trial',
'user' => $data,
));
}
}

先谢谢大家了

最佳答案

我认为问题出在

url: '/home/tryproduct/'

使用base_url()来制作ajax url路径的url。它会起作用的。

关于javascript - Codeigniter 中的 JQuery Ajax POST 不起作用,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/38474710/

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