javascript Promise 解析函数与解析匿名函数

Question

为什么它有效(基于 console.log 输出)

return new Promise(function(resolve) {
    var test = function() {
        console.log('rrrr');
        return $timeout(function(){},100);
    }
    resolve(test());
}

但这不是吗？

return new Promise(function(resolve) {
    resolve(function() {
        console.log('rrrr');
        return $timeout(function(){},100);
    });
}

Answer 1

因为顶部调用测试函数，但底部仅定义匿名函数。

试试这个，它应该有效:

return new Promise(function(resolve) {
    resolve(function() {
        console.log('rrrr');
        return $timeout(function(){},100);
    }()); // the extra () will call your anonymous function.
}