bash - ssh bash从远程文件接收变量

Question

我需要通过SSH从远程文件中读取变量并进行比较。但是我得到了格式错误的变量。如何正确做？

    #!/bin/bash 
    pass='dpassspass'
    user='root@10.10.19.18'
    IP="10.2.1.41"
    path=/sys/variable/serv
    #not work## No such file or directory# write=$(sshpass -p $ovhpass ssh -t $user echo "$IP" > $path)
    sshpass -p $pass ssh -t $user  << EOF
    echo "$IP" > $path
    EOF
    my_var=$(sshpass -p $pass ssh -t $user "cd /sys_ovh; ./serv.bash")
    echo mystart-"$my_var"-myend
    read=$(sshpass -p $pass ssh -t $user cat $path)
    echo start-"$read"-end
    echo start-"$IP"-end
    if [ "$read" == "$IP" ]; then 
    echo "run"
    fi

输出:

Connection to 10.10.19.18 closed.
-myendt-10.2.1.41
Connection to 10.10.19.18 closed.
-endt-10.2.1.41
start-10.2.1.41-end

我在哪里弄错了？如何从SSH获取数据？

Answer 1

vars my_var和read填充了以'\ r'结尾的字符串，告诉echo返回到第一列。我认为您的本地脚本存在问题。您可以使用

tr -d "\r" < myfile > myfile2