javascript - 计算直线下降

Question

我今年拥有值(value) 1000 的 Assets (比如车辆)...

var assetCurrentBookValue = 1000

车辆会在5年内贬值...也就是说 future 5年内值(value)会变成0...

var assetLife = 5

每年折旧变成...

var assetYearlyDepreciation = assetCurrentBookValue / assetLife

我需要像这样计算每年折旧后的年度值(value)......

year    assetYearlyDepreciation         assetBookVaue
2016    200                                     1000
2017    200                                     800
2018    200                                     600
2019    200                                     400
2020    200                                     200
2021    200                                     0

我需要像这样转换成数组...

[
    [2016,1000],
    [2017,800],
    [2018,600],
    [2019,400],
    [2020,200],
    [2021,0]
]

这是我的解决方法...

var index = Array.from(Array(assetLife).keys());
var thisYear = new Date().getFullYear()

var assetYearlyBookValue = [[thisYear,assetCurrentBookValue]]

index.forEach((o) => {
    assetYearlyBookValue.push([o + thisYear + 1, assetCurrentBookValue - assetYearlyDepreciation])
});

但是我得到了..

[
    [2016,1000],
    [2017,800],
    [2018,800],
    [2019,800],
    [2020,800],
    [2021,800]
]

任何帮助将不胜感激...谢谢你..

Answer 1

修改 assetCurrentBookValue - assetYearlyDepreciation 和 new Date().getFullYear() 的结果并将它们存储到变量中，以便您可以获得持续变化的结果:

var index = Array.from(Array(assetEconomicLife).keys());
var thisYear = new Date().getFullYear()

var assetYearlyBookValue = [[thisYear,assetCurrentBookValue]]
var lastRes = assetCurrentBookValue

index.forEach((o) => {
    lastRes -= assetYearlyDepreciation
    assetYearlyBookValue.push([o + (++thisYear), lastRes])
});