gpt4 book ai didi

java - 当尝试部分模拟 void 方法时,我收到 NotAMockException - 我做错了什么?

转载 作者:行者123 更新时间:2023-12-02 13:56:06 33 4
gpt4 key购买 nike

我正在尝试一起使用两种 Mockito 模式:

  • 对于部分模拟,请使用 Mockito.spy
  • 对于返回 void 的模拟方法,请使用 Mockito.doXXX(...).when(mock).method(matchers),因为您不能使用 Mockito.when(出于明显原因的mock.method(matchers))语法(method返回void,因此不能作为参数传递)

当组合它们时,我遇到了 NotAMockException。下面是一个(人为的)示例,我使用 PowerMockito 1.6.2 (=Mockito 1.10.19) 和 JUnit 4.12 进行了测试,并重现了该问题。

public class Greeter { // this is the class we will be partially mocking
public void helloWorld(String hello, Set<String> set) {
set.add("Hello: "+hello);
}

public void goodbyeWorld(String goodbye, Set<String> set) {
set.add("Goodbye: "+goodbye);
}
}

public class ExampleClass { // this is the class under test
public String helloGoodbye(String input, Greeter greeter) {
Set<String> helloSet = new HashSet<String>();
Set<String> goodbyeSet = new HashSet<String>();
greeter.helloWorld(input, helloSet);
greeter.goodbyeWorld(input, goodbyeSet);
return (helloSet.iterator().next() + ", " + goodbyeSet.iterator().next());
}
}

public class ExampleClassTest {
@Test
public void test() {
Greeter greeter = new Greeter();
Mockito.spy(greeter);
Mockito.doAnswer(new Answer(){ // exception thrown points to this line
@Override
public Void answer(InvocationOnMock invocation) throws Throwable {
((Set<String>)invocation.getArguments()[1]).add("Bonjour: " + invocation.getArguments()[0]);
return null;
}
}).when(greeter).helloWorld(Mockito.any(String.class), Mockito.any(Set.class));

ExampleClass example = new ExampleClass();
String aggregateGreeting = example.helloGoodbye("Mars", greeter);
Assert.assertEquals("Bonjour: Mars, Goodbye: Mars", aggregateGreeting);
}
}

这是我得到的完整错误:

org.mockito.exceptions.misusing.NotAMockException: 
Argument passed to when() is not a mock!
Example of correct stubbing:
doThrow(new RuntimeException()).when(mock).someMethod();
at com.example.ajb.pmv.ExampleClassTest.test(ExampleClassTest.java:21)
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:57)
at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43)
at org.junit.runners.model.FrameworkMethod$1.runReflectiveCall(FrameworkMethod.java:50)
at org.junit.internal.runners.model.ReflectiveCallable.run(ReflectiveCallable.java:12)
at org.junit.runners.model.FrameworkMethod.invokeExplosively(FrameworkMethod.java:47)
at org.junit.internal.runners.statements.InvokeMethod.evaluate(InvokeMethod.java:17)
at org.junit.runners.ParentRunner.runLeaf(ParentRunner.java:325)
at org.junit.runners.BlockJUnit4ClassRunner.runChild(BlockJUnit4ClassRunner.java:78)
at org.junit.runners.BlockJUnit4ClassRunner.runChild(BlockJUnit4ClassRunner.java:57)
at org.junit.runners.ParentRunner$3.run(ParentRunner.java:290)
at org.junit.runners.ParentRunner$1.schedule(ParentRunner.java:71)
at org.junit.runners.ParentRunner.runChildren(ParentRunner.java:288)
at org.junit.runners.ParentRunner.access$000(ParentRunner.java:58)
at org.junit.runners.ParentRunner$2.evaluate(ParentRunner.java:268)
at org.junit.runners.ParentRunner.run(ParentRunner.java:363)
at org.junit.runner.JUnitCore.run(JUnitCore.java:137)
at com.intellij.junit4.JUnit4IdeaTestRunner.startRunnerWithArgs(JUnit4IdeaTestRunner.java:74)
at com.intellij.rt.execution.junit.JUnitStarter.prepareStreamsAndStart(JUnitStarter.java:211)
at com.intellij.rt.execution.junit.JUnitStarter.main(JUnitStarter.java:67)
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:57)
at com.intellij.rt.execution.application.AppMain.main(AppMain.java:134)


Process finished with exit code -1

任何解决方法(实现模拟类中单个 void 方法的其他方法)也将受到欢迎!!

最佳答案

您没有将 spy 传递给 when()。您正在传递原始对象。

换行

Mockito.spy(greeter);

greeter = Mockito.spy(greeter);

Mockito.spy() 创建一个 spy 对象,它是原始对象的副本。它不会修改原始对象。

关于java - 当尝试部分模拟 void 方法时,我收到 NotAMockException - 我做错了什么?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/32791897/

33 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com