javascript - 如何在 CI 中向 json 对象添加循环数据？

Question

我试图将循环数据合并到 json 对象，每次我只得到循环的最后一个结果，所以我将该变量声明为数组，它来得很好，我得到了结果，但格式不正确，有额外的方括号，这是我不想要的，因为在前端解析时，它会产生问题。

下面我提供了我的代码。

{

  "status": "success",
  "statusReason": "Favouritelist",
  "result": {
    "Favouritelist": [
      [ //want to remove this square bracket
        {
          "branch_id": "1234",
          "branch_name": "avis1",
          "branch_image": "uploads/avis.png",
          "branch_gps": "12.9250,77.5938",
          "branch_address": "eredfdf",
          "branch_phone": "2147483647",

        }
      ],//want to remove this square bracket
      [//want to remove this square bracket
        {
          "branch_id": "1234",
          "branch_name": "avis1",
          "branch_image": "uploads/avis.png",
          "branch_gps": "12.9250,77.5938",
          "branch_address": "eredfdf",
          "branch_phone": "2147483647",


        }
      ]//want to remove this square bracket
    ]
  }
}

我的 CI 代码

foreach ($tempquery->result() as $res1){
         $car_id = $res1->car_id;  

       if(empty($timestamp)){

 $this->db->select("IFNULL(branch.branch_id,'') as branch_id,IFNULL(branch.name,'') as branch_name,IFNULL(branch.image,'') as branch_image,IFNULL(branch.gps,'') as branch_gps,IFNULL(branch.address,'')as branch_address,IFNULL(branch.phone,'')as branch_phone,(select IFNULL(avg(rating),0) from branch_rating where user_id='$user_id'  and delete_status ='false' )as branch_rating,IFNULL(car_id,'') as car_id,IFNULL(cars.name,'') as car_name,IFNULL(cars.image,'') as car_image,IFNULL(model,'') as model,IFNULL(price,'')as price,IFNULL(year,'')as year,IFNULL(type,'')as type,IFNULL(`no_of_seats`,'')as `no_of_seats`,IFNULL(`gear_type`,'') as `gear_type`,IFNULL(color,'') as color,insurance,status,IFNULL(description,'') as description,(select IFNULL(avg(rating),0) from car_rating where user_id='$user_id'  and delete_status ='false' )as car_rating,car_types.typename AS carType,cars.petrol_type,car_types.car_type_id,cars.delivery_charges,cars.services");
 $this->db->from("branch");
 $this->db->join("cars","branch.branch_id=cars.branch_id");
 $this->db->join('car_types', 'cars.car_type_id = car_types.car_type_id');
 $this->db->where("cars.car_id",$car_id);
 $this->db->where("branch.delete_status" , "false");
 $this->db->where("cars.delete_status" , "false");
$car_details= $this->db->get();  
 $cdetail_new[]=$car_details->result(); ///added [] to mearge dat


           }

 Response::code_200("Favouritelist", array("Favouritelist" => $cdetail_new));  

任何人都可以建议我，我哪里做错了..

ADV 谢谢

Answer 1

看起来源代码中包含了数组。这里的 result() 函数也许将其作为数组提供？

$car_details->result();

如果是这种情况，您可能想在此处打开它。如果您使用的是最新版本的 PHP，则可以使用此表示法:

$cdetail_new[] = $car_details->result()[0];

如果没有，请尝试旧的:

$result = $car_details->result();
$cdetail_new[] = $result[0];

您可以检查这是否是问题所在，即，result() 是否以包含单个元素的数组形式提供输出:

$car_details = $this->db->get();
var_dump($car_details->result());  // Is this resulting as an array?
die();
$cdetail_new[] = $car_details->result(); ///added [] to mearge dat