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sql-server - 根据每 n 个时间间隔选择行

转载 作者:行者123 更新时间:2023-12-02 13:43:43 26 4
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我有一个表,其中包含主键(bigint)、日期时间、值、外键到配置表,该表由 100,000 行组成。我希望能够获取可变时间间隔的行。例如。

    Select Timestamp, value from myTable where configID=3 
AND{most recent for 15 min interval}

我有一个 CTE 查询,它返回间隔间隔内的多行

    WITH Time_Interval(timestamp, value, minutes)
AS
(
Select timestamp, value, DatePart(Minute, Timestamp) from myTable
Where Timestamp >= '12/01/2012' and Timestamp <= 'Jan 10, 2013' and
ConfigID = 435 and (DatePart(Minute, Timestamp) % 15) = 0
)
Select Timestamp, value, minutes from Time_Interval
group by minutes, value, timestamp
order by Timestamp

如:

  2012-12-19 18:15:22.040   6.98    15
2012-12-19 18:15:29.887 6.98 15
2012-12-19 18:15:33.480 7.02 15
2012-12-19 18:15:49.370 7.01 15
2012-12-19 18:30:41.920 6.95 30
2012-12-19 18:30:52.437 6.93 30
2012-12-19 19:15:18.467 7.13 15
2012-12-19 19:15:34.250 7.11 15
2012-12-19 19:15:49.813 7.12 15

但可以看出,第一个 15 分钟间隔有 4 个,下一个间隔有 2 个,依此类推...更糟糕的是,如果在 15 分钟的精确时间戳处没有获取到数据,则没有任何值(value)。

我想要的是十五分钟间隔的最新值...如果该间隔的唯一数据发生在间隔开始后 1 秒。

我正在考虑 Lead/over,但是再次......行并不是这样组织的。主键是一个bigInt,并且是一个聚集索引。 Timstamp 列和 ConfigID 列均已建立索引。上述查询在一秒内返回 4583 行。

感谢您的帮助。

最佳答案

试穿一下尺寸。当给定间隔有多个时间戳时,它甚至可以处理返回一行。注意:这假设您的 Bigint PK 列名为:idx。如果不是,只需替换您看到“idx”的位置即可。

    ;WITH Interval_Helper([minute],minute_group)
AS
(
SELECT 0, 1 UNION SELECT 1, 1 UNION SELECT 2, 1 UNION SELECT 3, 1 UNION SELECT 4, 1
UNION SELECT 5, 1 UNION SELECT 6, 1 UNION SELECT 7, 1 UNION SELECT 8, 1 UNION SELECT 9, 1
UNION SELECT 10, 1 UNION SELECT 11, 1 UNION SELECT 12, 1 UNION SELECT 13, 1 UNION SELECT 14, 1
UNION SELECT 15, 2 UNION SELECT 16, 2 UNION SELECT 17, 2 UNION SELECT 18, 2 UNION SELECT 19, 2
UNION SELECT 20, 2 UNION SELECT 21, 2 UNION SELECT 22, 2 UNION SELECT 23, 2 UNION SELECT 24, 2
UNION SELECT 25, 2 UNION SELECT 26, 2 UNION SELECT 27, 2 UNION SELECT 28, 2 UNION SELECT 29, 2
UNION SELECT 30, 3 UNION SELECT 31, 3 UNION SELECT 32, 3 UNION SELECT 33, 3 UNION SELECT 34, 3
UNION SELECT 35, 3 UNION SELECT 36, 3 UNION SELECT 37, 3 UNION SELECT 38, 3 UNION SELECT 39, 3
UNION SELECT 40, 3 UNION SELECT 41, 3 UNION SELECT 42, 3 UNION SELECT 43, 3 UNION SELECT 44, 3
UNION SELECT 45, 4 UNION SELECT 46, 4 UNION SELECT 47, 4 UNION SELECT 48, 4 UNION SELECT 49, 4
UNION SELECT 50, 4 UNION SELECT 51, 4 UNION SELECT 52, 4 UNION SELECT 53, 4 UNION SELECT 54, 4
UNION SELECT 55, 4 UNION SELECT 56, 4 UNION SELECT 57, 4 UNION SELECT 58, 4 UNION SELECT 59, 4

)
,Time_Interval([timestamp], value, [date], [hour], minute_group)
AS
(
SELECT A.[Timestamp]
,A.value
,CONVERT(smalldatetime, CONVERT(char(10), A.[Timestamp], 101))
,DATEPART(HOUR, A.[Timestamp])
,B.minute_group
FROM myTable A
JOIN Interval_Helper B
ON (DATEPART(minute, A.[Timestamp])) = B.[minute]
AND A.[Timestamp] >= '12/01/2012'
AND A.[Timestamp] <= '01/10/2013'
AND A.ConfigID = 435
)
,Time_Interval_TimeGroup([date], [hour], [minute], MaxTimestamp)
AS
(
SELECT [date]
,[hour]
,minute_group
,MAX([Timestamp]) as MaxTimestamp
FROM Time_Interval
GROUP BY [date]
,[hour]
,minute_group
)
,Time_Interval_TimeGroup_Latest(MaxTimestamp, MaxIdx)
AS
(
SELECT MaxTimestamp
,MAX(idx) as MaxIdx
FROM myTable A
JOIN Time_Interval_TimeGroup B
ON A.[Timestamp] = B.MaxTimestamp
GROUP BY MaxTimestamp
)


SELECT A.*
FROM myTable A
JOIN Time_Interval_TimeGroup_Latest B
ON A.idx = B.MaxIdx
ORDER BY A.[timestamp]
<小时/>

这是来自@MntManChris 的巧妙时间组函数的另一种表现:

CREATE FUNCTION dbo.fGetTimeGroup (@DatePart tinyint, @Date datetime)
RETURNS int
AS
BEGIN
RETURN CASE @DatePart
WHEN 1 THEN DATEPART(mi, @Date)
WHEN 2 THEN DATEPART(mi, @Date)/5 + 1 -- 5 min
WHEN 3 THEN DATEPART(mi, @Date)/15 + 1 -- 15 min
WHEN 4 THEN DATEPART(mi, @Date)/30 + 1 -- 30 min
WHEN 5 THEN DATEPART(hh, @Date) -- hr
WHEN 6 THEN DATEPART(hh, @Date)/6 + 1 -- 6 hours
WHEN 7 THEN DATEPART(hh, @Date)/12 + 1 -- 12 hours
WHEN 8 THEN DATEPART(d, @Date) -- day
ELSE -1
END
END

关于sql-server - 根据每 n 个时间间隔选择行,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/16530755/

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