function - 通用顶级功能引用

Question

我如何引用以下function

@SinceKotlin("1.3")
public fun <T> sequence(@BuilderInference block: suspend SequenceScope<T>.() -> Unit): Sequence<T> = Sequence { iterator(block) }

尝试中

val sequenceFunction: KFunction<Sequence<Int>> = ::sequence

导致编译时错误

Type inference failed: Not enough information to infer parameter T in fun sequence(block: suspend SequenceScope.() -> Unit): SequencePlease specify it explicitly.

Answer 1

val f: (suspend SequenceScope<Int>.() -> Unit) -> Sequence<Int> = ::sequence

工作了
注意:获得的对象是某种包装函数类型。不是实际的函数声明。运行 this可以证明这一点。