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java - 程序未从 URL 读取输入

转载 作者:行者123 更新时间:2023-12-02 13:20:56 25 4
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所以我的程序应该从 URL 读取名称列表,以便玩猜名字游戏;但是,该程序似乎无法从 URL 读取任何内容,更不用说将其添加到 ArrayList 中了。运行程序时,我得到的只是“此列表中有 0 个名称”,这意味着尚未从 URL 添加任何名称。

当我使用调试器并单步执行 URL 时,收到一条错误消息“无法单步执行,选定的线程未挂起”。

import java.io.IOException;
import java.net.MalformedURLException;
import java.net.URL;
import java.util.ArrayList;
import java.util.Collections;
import java.util.Scanner;

public class NameGuesser {
private ArrayList<String> lastNames = new ArrayList<String>();
Scanner input = new Scanner(System.in);
public void readNames() throws IOException, MalformedURLException {
// Read the last names

URL url = new URL(
"http://www2.census.gov/topics/genealogy/1990surnames/dist.all.last");

Scanner in = new Scanner(url.openStream());
while (in.hasNext()) {
// Read the last name
String lastName = in.next();
lastNames.add(lastName);

// Ignore the statistical information
// in.nextDouble();
// in.nextDouble();
// in.nextInt();
}
in.close();

// Print out the number of names in the file and
// Sort the names using Collections
Collections.sort(lastNames);
System.out.println("There are " + lastNames.size() + " names in this list");
}

public int guessName() {
int counter = 0;
int low = 0;
int high = lastNames.size();
int mid = high / 2;
boolean notFound = true; //variables to hold game info
String userInput = "";
while (notFound) { //while the name is not found
System.out.println("Does your name come before " + lastNames.get(mid) + " in the dictionary? (Y/N), or is " + lastNames.get(mid) + " your name? (S)");
userInput = input.next(); //ask if it is in the middle
if (userInput.equalsIgnoreCase("Y")) { //if before, set new upper bound
high = mid;
mid = ((high - low)/2) + low;
counter++;
} else if(userInput.equalsIgnoreCase("N")){ //if after, set new lower bound
counter++;
low = mid;
mid = ((high - low)/2) + low;
}
else{ //if name is found, return counter
System.out.println("Your name, " + lastNames.get(mid) + ", was found with " + counter + " guesses.");
input.close();
return counter;
}
if(high == low){ //if upper and lower bounds are equal
System.out.println("Is your name: " + lastNames.get(mid) + " ? (Y/N)");
userInput = input.next(); //ask if name is found
if(userInput.equalsIgnoreCase("Y")){ //if yes, print success, counter, and return counter
System.out.println("Your name, " + lastNames.get(mid) + ", was found with " + counter + " guesses.");
input.close();
return counter;
}
else if(userInput.equalsIgnoreCase("N")){ //if no, inform user that guesser failed
System.out.println("Name not found. Attempted locating with " + counter + " guesses");
input.close();
return counter;
}
}
}
input.close();
return counter;
}
}

测试方法:

import java.io.IOException;
import java.net.MalformedURLException;


public class NameGame {

public static void main(String[] args) throws MalformedURLException, IOException {
NameGuesser game = new NameGuesser();

game.readNames();
}
}

最佳答案

您是否尝试过在浏览器中打开该 URL?它重定向到安全协议(protocol) (HTTPS)。将您的 URL 更改为“https://www2.census.gov/topics/genealogy/1990surnames/dist.all.last ”,它应该可以正常工作。

关于java - 程序未从 URL 读取输入,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/43563945/

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