java - 在十二生肖确定器中接收有效输入的无效 I/O

Question

我是一名初学者编码器，我正在开发一个确定星座的项目。

问题:“else if”日期根据用户输入的月份和日期准确确定星座运势，但对于“if” ” 陈述例如五月双子座日期。对于 5 月 21 日至 5 月 31 日之间输入的任何日期，我都收到无效输入。我已尝试重写该案例，但仍然存在问题。

如果有人能看到我看不到的东西并让我知道，我将非常感激。谢谢!

switch (month) {

    case 1:
        if (month == 12 && day >= 22 && day <= 31)
            zodiac = "Capricorn";
        else if (month == 01 && day < 20)
            zodiac = "Capricorn";
        else
            zodiac = "Invalid Input";
        break;
    case 2:
        if (month == 1 && day >= 20 && day < 32)
            zodiac = "Aquarius";
        else if (month == 2 && day < 19)
            zodiac = "Aquarius";
        else
            zodiac = "Invalid Input";
        break;
    case 3:
        if (month == 2 && day >= 19 && day <= 29)
            zodiac = "Pisces";
        else if (month == 3 && day < 21)
            zodiac = "Pisces";
        else
            zodiac = "Invalid Input";
        break;
    case 4:
        if (month == 3 && day >= 21 && day < 32)
            zodiac = "Aries";
        else if (month == 4 && day < 20)
            zodiac = "Aries";
        else
            zodiac = "Invalid Input";
        break;
    case 5:
        if (month == 4 && day >= 20 && day < 31)
            zodiac = "Taurus";
        else if (month == 5 && day < 21)
            zodiac = "Taurus";
        else
            zodiac = "Invalid Input";
        break;
    case 6:
        if (month == 5 && day >= 21 && day < 32)
            zodiac = "Gemini";
        else if (month == 6 && day < 21)
            zodiac = "Gemini";
        else
            zodiac = "Invalid Input";
        break;
    case 7:
        if (month == 6 && day >= 21 && day < 31)
            zodiac = "Cancer";
        else if (month == 7 && day < 23)
            zodiac = "Cancer";
        else
            zodiac = "Invalid Input";
        break;
    case 8:
        if (month == 7 && day >= 23 && day < 32)
            zodiac = "Leo";
        else if (month == 8 && day < 23)
            zodiac = "Leo";
        else
            zodiac = "Invalid Input";
        break;
    case 9:
        if (month == 8 && day >= 23 && day < 32)
            zodiac = "Virgo";
        else if (month == 9 && day < 23)
            zodiac = "Virgo";
        else
            zodiac = "Invalid Input";
        break;
    case 10:
        if (month == 9 && day >= 23 && day < 31)
            zodiac = "Libra";
        else if (month == 10 && day < 23)
            zodiac = "Libra";
        else
            zodiac = "Invalid Input";
        break;
    case 11:
        if (month == 10 && day >= 23 && day < 32)
            zodiac = "Scorpio";
        else if (month == 11 && day < 22)
            zodiac = "Scorpio";
        else
            zodiac = "Invalid Input";
        break;
    case 12:
        if (month == 11 && day >= 22 && day < 31)
            zodiac = "Sagittarius";
        else if (month == 12 && day < 22)
            zodiac = "Sagittarius";
        else
            zodiac = "Invalid Input";
        break;

Answer 1

在您的 switch 语句中，已根据您设置的情况完成了当月的检查。在情况 1 中，月份为 1，依此类推...

我建议您将 switch 语句中的逻辑重写为如下所示:

switch (month) {

case 1: // --> month == 1 here
    if (day < 20) {
        zodiac = "Capricorn";
    } else if (day >= 20 && day <=31) {
        zodiac = "Aquarius";
    }
case 2: // --> month == 2 here
    if (day < 19) {
        zodiac = "Aquarius";
    } else if (day >= 19 && day <= 29)
        zodiac = "Pisces";
    break;

    // etc 
}