java - 如何在java中将一个不带空格的字符串分割成多个单词？

Question

这个问题已经有答案了:

Split a string, at every nth position (5 个回答)

已关闭 9 年前。

我有一个String数组

String student [] = {"BAT4M0ABBB4M0ABOH4M0CCHI4U0AENG4U0DMDM4U0B"}

我需要将其分割为每 7 个字符。它应该看起来像这样:

String student {
"BAT4M0A",
"BBB4M0A",
"BOH4M0C",
"CHI4U0A",
"ENG4U0D",
"MDM4U0B"
}

这是我到目前为止的代码。

       for (int i=0; i<= data.length; i++)
        {
          student= data[i].split(","); //data is a file of 1000 lines that is being read
          if (student [2].equals(sN)) //student is a line in the each file that has been  split into 11 parts
        {
            String timetable[]= student[9].split("(?<=\\G.......)");
            System.out.println (timetable);
            break;
        }

Answer 1

你可以做

String[] array = student[0].split("(?<=\\G.{7})");

\G是与最后一个匹配项匹配的元字符，因此 (?<=\\G.{7})匹配空字符串后跟任意 7 个字符

• IDEOne Demo