android - Kotlin 命名构造函数

Question

我在 中有以下代码飞镖 编程语言

class HttpResponse {
  final int code;
  final String? error;

  HttpResponse.ok() : code = 200; <== This functionality 
  HttpResponse.notFound()         <== This functionality
      : code = 404,
        error = 'Not found';

  String toString() {
    if (code == 200) return 'OK';
    return 'ERROR $code ${error.toUpperCase()}';
  }
}

我如何在 Kotlin 中实现这一点，我知道我可以使用静态方法，但是静态方法没有初始化类的目的，有没有办法在 Kotlin 中实现这一点？

Answer 1

您正在寻找 Sealed Classes .

sealed class HttpResponse(val code: Int, val error: String? = null) {
    
    class Ok(code: Int) : HttpResponse(code)
    
    class NotFound(code: Int, error: String?) : HttpResponse(code, error)
    
    override fun toString(): String {
        return if (code == 200) "OK"
        else "ERROR $code ${error?.toUpperCase()}"
    }
}

fun main() {
    val okResponse = HttpResponse.Ok(200)
    val notFoundResponse = HttpResponse.NotFound(404, "Not found")
}