java - 如何让 nextLine() 等待用户的输入？

Question

这个问题已经有答案了:

Scanner is skipping nextLine() after using next() or nextFoo()? (25 个回答)

已关闭 6 年前。

    for (int i = 1; i <= value; i++) {
        System.out.print("Player " + i + ", Please Enter your name : ");
        String PlayerName = input.nextLine();
        System.out.print("Please enter a number between 0 and 9 : ");
        int PlayerNumber = input.nextInt();
        System.out.println(PlayerName + " : " + PlayerNumber);
    }

输出:Player 1, Please Enter your name : Please enter a number between 0 and 9 :

如果我改变input.nextLine至input.next ，它将等待用户第一次输入，但他/她将无法写下他们的全名。

我的问题:我可以更改什么以便用户可以先输入他的全名，然后输入他的电话号码？

Answer 1

在input.nextInt()之后使用newLine

for (int i = 1; i <= value; i++) {
    input.nextLine(); //add this to top
    System.out.print("Player " + i + ", Please Enter your name : ");
    String PlayerName = input.nextLine();
    System.out.print("Please enter a number between 0 and 9 : ");
    int PlayerNumber = input.nextInt();

    System.out.println(PlayerName + " : " + PlayerNumber);
}