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java - Java中序列化JSON到JSON-LD的代码示例?

转载 作者:行者123 更新时间:2023-12-02 13:04:58 24 4
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我需要将以 JSON 形式表示的大量数据转换为 JSON-LD。我想用this来做到这一点JSON-LD Java实现,但我不明白,我该怎么办。

我在网上看了几个教程并阅读了一些有关 JSON-LD 的内容,但不明白最简单的事情:如何将 JSON 转换为 JSON -LD

例如,我有以下 JSON 代码:

{
"name" : "Andreas",
"age" : 20,
"profession" : "student",
"personalWebsite" : "example.com"
}

我现在应该做什么?类似于 context.add("example.com")

InputStream inputStream = new FileInputStream("C:\Users\Username\input.json");
Object jsonObject = JsonUtils.fromInputStream(inputStream);
Map context = new HashMap();
JsonLdOptions options = new JsonLdOptions();

最佳答案

向您的数据添加“@context”条目。

{
"name" : "Andreas",
"age" : 20,
"profession" : "student",
"personalWebsite" : "example.com",
"@context":"http://schema.org/"
}

您的 JSON-LD 处理器将完成剩下的工作(自版本 0.9 起)

作为测试,您可以将 json 转换为 rdf。

package overflow.stack2449461;

import java.io.ByteArrayInputStream;
import java.io.InputStream;
import java.io.StringWriter;
import java.util.Collection;


import org.eclipse.rdf4j.model.Statement;
import org.eclipse.rdf4j.rio.RDFFormat;
import org.eclipse.rdf4j.rio.RDFHandlerException;
import org.eclipse.rdf4j.rio.RDFParser;
import org.eclipse.rdf4j.rio.RDFWriter;
import org.eclipse.rdf4j.rio.Rio;
import org.eclipse.rdf4j.rio.helpers.StatementCollector;


public class Test {
@org.junit.Test
public void testForYourCode() {
String data = "{\"name\" : \"Andreas\",\"age\" : 20,\"profession\" : \"student\", \"personalWebsite\" : \"example.com\",\"@context\": \"http://schema.org/\"}";
try (InputStream in = new ByteArrayInputStream(data.getBytes("utf-8"))) {
String dataAsRdf = readRdfToString(in, RDFFormat.JSONLD, RDFFormat.NTRIPLES, "");
System.out.println(dataAsRdf);
} catch (Exception e) {
throw new RuntimeException(e);
}
}

/**
* @param in
* a rdf input stream
* @param inf
* the rdf format of the input stream
* @param outf
* the output format
* @param baseUrl
* usually the url of the resource
* @return a string representation
*/
public static String readRdfToString(InputStream in, RDFFormat inf, RDFFormat outf, String baseUrl) {
Collection<Statement> myGraph = null;
myGraph = readRdfToGraph(in, inf, baseUrl);
return graphToString(myGraph, outf);
}

/**
* @param inputStream
* an Input stream containing rdf data
* @param inf
* the rdf format
* @param baseUrl
* see sesame docu
* @return a Graph representing the rdf in the input stream
*/
public static Collection<Statement> readRdfToGraph(final InputStream inputStream, final RDFFormat inf,
final String baseUrl) {
try {
final RDFParser rdfParser = Rio.createParser(inf);
final StatementCollector collector = new StatementCollector();
rdfParser.setRDFHandler(collector);
rdfParser.parse(inputStream, baseUrl);
return collector.getStatements();
} catch (final Exception e) {
throw new RuntimeException(e);
}
}

/**
* Transforms a graph to a string.
*
* @param myGraph
* a sesame rdf graph
* @param outf
* the expected output format
* @return a rdf string
*/
public static String graphToString(Collection<Statement> myGraph, RDFFormat outf) {
StringWriter out = new StringWriter();
RDFWriter writer = Rio.createWriter(outf, out);
try {
writer.startRDF();
for (Statement st : myGraph) {
writer.handleStatement(st);
}
writer.endRDF();
} catch (RDFHandlerException e) {
throw new RuntimeException(e);
}
return out.getBuffer().toString();
}

}

使用 pom.xml

   <dependency>
<groupId>org.eclipse.rdf4j</groupId>
<artifactId>rdf4j-runtime</artifactId>
<version>2.2</version>
<type>pom</type>
</dependency>
<dependency>
<groupId>com.github.jsonld-java</groupId>
<artifactId>jsonld-java</artifactId>
<version>0.10.0</version>
</dependency>

它将把你的 json 字符串打印为 rdf NTRIPLES

_:b0 <http://schema.org/age> "20"^^<http://www.w3.org/2001/XMLSchema#integer> .
_:b0 <http://schema.org/name> "Andreas" .
_:b0 <http://schema.org/personalWebsite> "example.com" .
_:b0 <http://schema.org/profession> "student" .

关于java - Java中序列化JSON到JSON-LD的代码示例?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/43219064/

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