java - 最后一个工作日期非假期

Question

我有以下Holiday类(class):

public class Holiday {

    private int day;
    private int month;


    public Holiday(GregorianCalendar calendar) {
        this.day = calendar.get(GregorianCalendar.DAY_OF_MONTH);
        this.month = calendar.get(GregorianCalendar.MONTH) + 1;
    }

}

枚举日:

public enum Day {

    SATURDAY(6), SUNDAY(7);

    private int index;

    Day(int index) {
        this.index = index;
    }

    public int getIndex() {
        return index;
    }
}


public class DateTool {

    private static final String DATE_FORMAT = "yyyy_MM_dd";

    public DateTool() {
        super();
    }


    public static String getPreviousWorkingDay(List<Holiday> listOfHolidays) {
            //derive the last working day that is not saturday/sunday
    }

    public static String parseDate(Date date) {
        return new SimpleDateFormat(DATE_FORMAT).format(date);
    }

    public static boolean isSunday(LocalDateTime date) {
        return date.getDayOfWeek().getValue() == Day.SUNDAY.getIndex();
    }

    public static boolean isSaturday(LocalDateTime date) {
        return date.getDayOfWeek().getValue() == Day.SATURDAY.getIndex();
    }

}

鉴于我有假期的列表，我如何计算并在getPreviousWorkingDay(...)中返回前一个工作日排除星期六和星期日的方法？

我正在尝试导出要查找的最后一个文件日期，因此我正在尝试解决这样的问题

  if (todayIsHoliday(listOfHolidays)) {
                getPreviousWorkingDay(listOfHolidays);
            }

所以如果当天是假期，请查看最后一个不是假期的日期并以字符串格式返回。

我不确定如何回顾。请注意，假期列表不仅包括周六和周日。它们是乡村假期，例如农历新年等。

我为此使用的是 java 8，因此欢迎任何重构或改进:)

Answer 1

private static final DateTimeFormatter dateFormatter
        = DateTimeFormatter.ofPattern("uuuu_MM_dd");

public static String getPreviousWorkingDay(List<MonthDay> listOfHolidays) {
    LocalDate workingDay = LocalDate.now(ZoneId.of("Pacific/Easter")).minusDays(1);
    while (workingDay.getDayOfWeek().equals(DayOfWeek.SATURDAY) 
            || workingDay.getDayOfWeek().equals(DayOfWeek.SUNDAY)
            || listOfHolidays.contains(MonthDay.from(workingDay))) {
        workingDay = workingDay.minusDays(1);
    }
    return workingDay.format(dateFormatter);
}

我正在使用 java.time，现代 Java 日期和时间 API，正如评论中提到的，我建议您也这样做。让我们看看上面的方法的实际效果:

    System.out.println(getPreviousWorkingDay(Collections.emptyList()));
    // Let’s say Valentin’s day is a holiday
    System.out.println(getPreviousWorkingDay(List.of(MonthDay.of(Month.FEBRUARY, 14))));
    // And so are Lent Monday and the death day of Danish would-be king Henrik 
    System.out.println(getPreviousWorkingDay(List.of(MonthDay.of(Month.FEBRUARY, 12), 
            MonthDay.of(Month.FEBRUARY, 13), MonthDay.of(Month.FEBRUARY, 14))));

今天打印了:

2018_02_14
2018_02_13
2018_02_09

(我有点作弊，因为四旬斋星期一不是每年的同一天；但我认为不需要考虑这些假期。)

由于确定今天的日期是一个时区敏感操作，如果不是复活节岛时区，请替换您所需的时区。编辑:在 Java 8 中使用 Arrays.asList() 而不是 Java 9 List.of()。

链接: Oracle tutorial: Date Time解释如何使用java.time。