Javaplayer_width和player_height错误

Question

我正在尝试制作这个游戏，现在我有一个可以移动的角色，但我想有效地改变角色的宽度和高度。因此，角色上下移动的尺寸与角色左右移动的尺寸不同，所以我做了这个 if 语句，如果玩家向上移动，那么宽度就是这个，如果玩家向右移动，那么 with 就是这样。但是当我写完代码时，它给了我两个错误:

Syntax error on token ";", { expected after this token
Syntax error, insert "}" to complete Block

有人可以告诉我出了什么问题吗？

代码如下:

public class player extends creature {
    // other code

    private static int player_width;
    private static int player_height = 70; // error 1 here

    if(currentimage == assets.player_up) {
        player_width = 50;
    } else if(currentimage == assets.player_down) {
        player_width = 50;
    } else if(currentimage == assets.player_right) {
        player_width = 60;
    } else if(currentimage == assets.player_left) {
        player_width = 60;
    } // error 2 here

    public player(game game, float x, float y) {
        super(x, y,player_width,player_height);
        this.game = game;

    }

这是生物构造函数:

public abstract class creature extends entity {

public static final int DEFAULT_HEALTH = 10;
public static final float DEFAULT_SPEED = 3.0f;
public static final int DEFAULT_CREATURE_WIDTH = 64,
        DEFAULT_CREATURE_HEIGHT = 64;

protected int health;
protected float speed;
protected float xMove, yMove;

public creature(float x, float y, int width, int height) {
    super(x, y, width, height);
    health = DEFAULT_HEALTH;
    speed = DEFAULT_SPEED;
    xMove = 0;
    yMove = 0;

}

Answer 1

嗯，你应该将这些 if 语句放在你的构造函数中。如果它们位于类内而不是方法内，则它们不会运行。只需将它们放入您的

public player(game game, float x, float y)

方法，你应该是金子。

注意:只是一个旁注，类名应该大写，这样更容易阅读代码。