java - 按子列表的值对 LIst 列表进行排序

Question

private List<String> subList;
private List<List<String>> records = new ArrayList<List<String>>();

for(....){

    subList = new ArrayList<String>();
    ...populate..
    records.add(subList);
}

例如，subList 有三个字符串 - a、b 和 c。我想按 subList 中 b 的值对记录进行排序。

records at 0 has a list of "10", "20", "30"
records at 1 has a list of "10", "05", "30"
records at 2 has a list of "10", "35", "30"

排序后，记录的顺序应该是 -

records at 0 = records at 1 above
records at 1 = records at 0 above
records at 2 = records at 2 above

什么是一个好的算法？

Answer 1

类似于:

Collections.sort(records, new Comparator<List<String>>()
{
  public int compare(List<String> o1, List<String> o2)
  {
    //Simple string comparison here, add more sophisticated logic if needed.
    return o1.get(1).compareTo(o2.get(1));
  }
})

虽然我发现对位置进行硬编码在实践中有点可疑，但您的意见可能会有所不同。