java - 如何对数字求和并乘以它们的序列计数(Java)？

Question

输入来自控制台，作为一行，包含数字。每个数字后面都有一个字符(S、H、D 或 C)。需要对数字求和，并且仅当两个或多个字符连续出现时，才将总和乘以字符序列的计数。

For example, 2C 3C 5C 15S 10H 12H 2S 14D has value (2 + 3 + 5) * 3 + 15 + (10 + 12) * 2 + 2 + 14 = 105.

我只能提取和求和数字，但仅此而已。

public static void main(String[] args) throws IOException {
        BufferedReader br = new BufferedReader(new InputStreamReader(System.in));

        String[] input = br.readLine().split(" ");
        int sum = 0;

        for (String s : input) {
            String number = s.substring(0, s.length() - 1);
            sum += Integer.parseInt(number);
        }
        System.out.println(sum);
}    

提前致谢!

Answer 1

这样就可以了

public static void main(String[] args) throws IOException {
    BufferedReader br = new BufferedReader(new InputStreamReader(System.in));

    String[] input = br.readLine().split(" "); 
    int sum = 0;
    String tmpLetter = null;
    int tmpSum = 0;
    int count = 0;

    for (String s : input) { 
        int number = Integer.parseInt(s.substring(0, s.length() - 1));
        String letter = s.substring(s.length() - 1);

        if(tmpLetter == null || tmpLetter.equals(letter)){
            count++;
            tmpSum += number;
        } else {
            sum += tmpSum * count;
            count = 1;
            tmpSum = number;
        }
        tmpLetter = letter;
    }
    sum += tmpSum * count;
    System.out.println(sum);
}