java - 未找到 JAX-RS 的处理程序方法

Question

我有一个资源 JAX-RS

@Path("/profile")
public class ProfileResource {

    @GET
    @Path(value = "/{username}")
    public Response getProfile(
            @PathParam("username") String username,
            @Context UriInfo uriInfo
    ) throws URISyntaxException {
       ....
    }
}



    2017-07-29 20:37:41.940 DEBUG 4004 --- [nio-8080-exec-5] o.s.web.servlet.DispatcherServlet        : Successfully completed request
2017-07-29 20:38:01.223 DEBUG 4004 --- [nio-8080-exec-7] o.s.web.servlet.DispatcherServlet        : DispatcherServlet with name 'dispatcherServlet' processing GET request for [/profile/jonki]
2017-07-29 20:38:01.236 DEBUG 4004 --- [nio-8080-exec-7] s.w.s.m.m.a.RequestMappingHandlerMapping : Looking up handler method for path /profile/jonki
2017-07-29 20:38:01.236 DEBUG 4004 --- [nio-8080-exec-7] s.w.s.m.m.a.RequestMappingHandlerMapping : Did not find handler method for [/profile/jonki]
2017-07-29 20:38:01.237 DEBUG 4004 --- [nio-8080-exec-7] o.s.w.s.handler.SimpleUrlHandlerMapping  : Matching patterns for request [/profile/jonki] are [/**]
2017-07-29 20:38:01.237 DEBUG 4004 --- [nio-8080-exec-7] o.s.w.s.handler.SimpleUrlHandlerMapping  : URI Template variables for request [/profile/jonki] are {}
2017-07-29 20:38:01.237 DEBUG 4004 --- [nio-8080-exec-7] o.s.w.s.handler.SimpleUrlHandlerMapping  : Mapping [/profile/jonki] to HandlerExecutionChain with handler [ResourceHttpRequestHandler [locations=[ServletContext resource [/], class path resource [META-INF/resources/], class path resource [resources/], class path resource [static/], class path resource [public/]], resolvers=[org.springframework.web.servlet.resource.PathResourceResolver@36463b09]]] and 1 interceptor
2017-07-29 20:38:01.237 DEBUG 4004 --- [nio-8080-exec-7] o.s.web.servlet.DispatcherServlet        : Last-Modified value for [/profile/jonki] is: -1
2017-07-29 20:38:01.238 DEBUG 4004 --- [nio-8080-exec-7] o.s.web.servlet.DispatcherServlet        : Null ModelAndView returned to DispatcherServlet with name 'dispatcherServlet': assuming HandlerAdapter completed request handling
2017-07-29 20:38:01.238 DEBUG 4004 --- [nio-8080-exec-7] o.s.web.servlet.DispatcherServlet        : Successfully completed request
2017-07-29 20:38:01.238 DEBUG 4004 --- [nio-8080-exec-7] o.s.web.servlet.DispatcherServlet        : DispatcherServlet with name 'dispatcherServlet' processing GET request for [/error]
2017-07-29 20:38:01.239 DEBUG 4004 --- [nio-8080-exec-7] s.w.s.m.m.a.RequestMappingHandlerMapping : Looking up handler method for path /error

我没有找到 JAX-RS 的方法。我使用的是Spring Boot，没有做任何配置。

Answer 1

你无缘无故地混淆了技术。 Spring 有自己的 Web 框架，不需要 JAX-RS，而且 Spring Web 无论如何也不兼容 JAX-RS，这解释了为什么处理程序没有注册。请参阅this 。可以将 JAX-RS 与 Spring 依赖注入(inject)一起使用，但没有必要。请参阅this .