gpt4 book ai didi

在linux中从C代码调用汇编函数

转载 作者:行者123 更新时间:2023-12-02 12:21:47 25 4
gpt4 key购买 nike

我想从我的 C 程序调用打印函数。
汇编程序:

 #test.s
.text

.global _start
.global print
.type print, @function

_start:

call print

# and exit.

movl $0,%ebx # first argument: exit code.
movl $1,%eax # system call number (sys_exit).
int $0x80 # call kernel.

print:
# write our string to stdout.

movl $len,%edx # third argument: message length.
movl $msg,%ecx # second argument: pointer to message to write.
movl $1,%ebx # first argument: file handle (stdout).
movl $4,%eax # system call number (sys_write).
int $0x80 # call kernel.

mov $0, %eax
ret
.data

msg:
.ascii "Hello, world!\n" # the string to print.
len = . - msg # length of the string.

我可以使用以下方法组装和链接它:

$as test.s -o test.o
$ld test.o -o test

我可以将它作为程序执行,它输出“Hello, world!”但是当我尝试从 C 代码调用 print 时,如下所示:

#include <stdio.h>
extern int print();

int main(){
int g;
g = print();
printf("Hello from c!, %d\n", g);

}

它是使用以下方式编译的:

$gcc -c main.c test

它只是打印“Hello from c, 13”,这意味着该函数被调用并返回一些字符,但不打印任何内容!

我做错了什么?

附注当我尝试像这样编译 prog 时:

$as test.s -o test.o
$gcc -c main.c -o main.o
$gcc main.c test.o

我有一个错误:

/usr/bin/ld: test.o: in function `_start':
(.text+0x0): multiple definition of `_start'; /usr/lib/gcc/x86_64-pc-linux-gnu/9.2.0/../../../../lib/Scrt1.o:(.text+0x0): first defined here
/usr/bin/ld: test.o: relocation R_X86_64_32 against `.data' can not be used when making a PIE object; recompile with -fPIE
/usr/bin/ld: final link failed: nonrepresentable section on output
collect2: error: ld returned 1 exit status

最佳答案

好的,完成!谢谢clearlight

我可以编译所有使用

$as test.s -o test.o
$gcc -c main.c -o main.o
$gcc -no-pie main.c test.o

一切都会正常进行!

关于在linux中从C代码调用汇编函数,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/60352424/

25 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com