java - 从文件夹中读取所有日志文件

Question

我想读取文件夹中的所有日志文件。我现在只读取一个文件。我已将日志文件的路径设置为String dir。我有其他异常的列表，这些异常或多或少与 getExternalServiceException 执行相同的操作。如何使用 从 D:\\logs 读取所有日志文件for 循环 或每个循环。

警报 - 我需要使用 Java v1.6

public class CallingCheck 
{


    public void getExternalServiceException(String sPath) {
        BufferedReader br = null;
        try {
            File f = new File(sPath);
            if(f.isFile())
            {

            FileInputStream fis = new FileInputStream(sPath);
            DataInputStream dis = new DataInputStream(fis);
            br = new BufferedReader(new InputStreamReader(dis));
            String strLine;

            String sPattern = "at (.*)\\.(.*)\\(([^:]*):?([\\d]*)\\)";

            Pattern p = Pattern.compile(sPattern);

            boolean bFlag = false;
             int  iCount = 0;
             int totCount = 0;
            int exCount = 0;


            while ((strLine = br.readLine()) != null) {

                if((strLine.contains("com.shop.integration.exception.ExternalServiceException")))
                        //
                {   exCount++;
                    bFlag = true;

                }
                if(bFlag){

                    if((strLine.contains("** Error"))){


                    Matcher m = p.matcher(strLine);
                    if(m.find()){
                        totCount++;
                        iCount++;

                    if(iCount==1){
                        System.out.println("Class name:- " + m.group(3));
                        System.out.println("Line Number:- " + m.group(4));
                        System.out.println("ExternalServiceException occurence count: " + exCount);

                        System.out.println("ExternalServiceException stack trace count: " + totCount);

                    }
                    if(strLine.contains("at")){
                        String sTemp[] = strLine.split("\\s+at+\\s+");

                        strLine = sTemp[1];
                        strLine = "at   "+strLine;
                    }
                    System.out.println(strLine);


                    if(iCount == 5){
                        bFlag = false;  
                        iCount=0;
                    }

                    }
                }

            }
            }}}
         catch (Exception e) {
            System.out.println(e.getMessage());
        }finally{
            try{
            if(br != null){
                br.close();
            }
            }catch(Exception e){
                System.out.println(e.getMessage());
            }
        }
    }

    public static void main(String[] args)
    {
        String dir= "D:\\logs\\readLogFiles.txt";

        CallingCheck check = new CallingCheck();
        check.getExternalServiceException(dir);


    }


}

Answer 1

您可以使用File.listFiles :

File[] fileList = new File(directory).listFiles(new FilenameFilter() {
            @Override
            public boolean accept(File dir, String name) {
                return true; // we simply want all the files in this directory
                            // but you can edit to accept specific files
                           // only depending on certain conditions
            }
        });

for (File file : fileList) { 
    // handle each file - read/write etc
}

使用 lambda (Java 8) 更酷:

File[] fileList = new File(directory).listFiles((dir, name) -> {
    return true; // we simply want all the files in this directory
});