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java - 从服务器接收响应时出错?

转载 作者:行者123 更新时间:2023-12-02 12:19:29 25 4
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我正在制作一个应用程序,将一些数据存储在数据库中,然后检索它。在服务器端我使用 PHP,在客户端我有这个文件来获取输入并将其传递给 PHP 文件。

new AsyncTask<String, String, String>() {

JSONParser jsonParser = new JSONParser();
private ProgressBar pBar;
private String url_post_pet = "http://192.168.0.13/Android/post_pet.php";

// JSON Node names
private static final String TAG_SUCCESS = "success";

/**
* Before starting background thread Show Progress Dialog
*/
@Override
protected void onPreExecute() {
super.onPreExecute();
//pBar = new ProgressBar();
//pBar.setIndeterminate(false);
//pBar.setVisibility(View.VISIBLE);
}

@Override
protected String doInBackground(String... args) {
// Building Parameters
HashMap<String, String> params = new HashMap<>();
params.put("name", a);
params.put("breed", BREED);
params.put("type", TYPE);
params.put("images", "Whatever");
params.put("description", c);
params.put("coords", b);

// getting JSON Object
// Note that create product url accepts POST method
JSONObject json = jsonParser.makeHttpRequest(url_post_pet,
"POST", params);
// check log cat for response
Log.d("Create Response", json.toString());

// check for success tag
try {
int success = json.getInt(TAG_SUCCESS);

if (success == 1) {
// successfully created product
Intent i = new Intent(getApplicationContext(), MainActivity.class);
startActivity(i);

// closing this screen
finish();
} else {
// failed to create product
}
} catch (JSONException e) {
System.out.println("exception" + e);
e.printStackTrace();
}
System.out.println("nul");
return null;
}

/**
* After completing background task Dismiss the progress dialog
**/
protected void onPostExecute(String file_url) {
// dismiss the dialog once done
//pBar.dismiss();
}
}.execute();

}
});
}

另外,我有这个 JSONParser:

public class JSONParser {

String charset = "UTF-8";
HttpURLConnection conn;
DataOutputStream wr;
StringBuilder result;
URL urlObj;
JSONObject jObj = null;
StringBuilder sbParams;
String paramsString;

public JSONObject makeHttpRequest(String url, String method,
HashMap<String, String> params) {

sbParams = new StringBuilder();
int i = 0;
for (String key : params.keySet()) {
try {
if (i != 0){
sbParams.append("&");
}
sbParams.append(key).append("=")
.append(URLEncoder.encode(params.get(key), charset));

} catch (UnsupportedEncodingException e) {
e.printStackTrace();
}
i++;
}

if (method.equals("POST")) {
// request method is POST
try {
urlObj = new URL(url);
conn = (HttpURLConnection) urlObj.openConnection();
conn.setDoOutput(true);
conn.setRequestMethod("POST");
conn.setRequestProperty("Accept-Charset", charset);
conn.setReadTimeout(10000);
conn.setConnectTimeout(15000);
conn.connect();

paramsString = sbParams.toString();

wr = new DataOutputStream(conn.getOutputStream());
wr.writeBytes(paramsString);
wr.flush();
wr.close();

} catch (IOException e) {
e.printStackTrace();
}
}
else if(method.equals("GET")){
// request method is GET

if (sbParams.length() != 0) {
url += "?" + sbParams.toString();
}

try {
urlObj = new URL(url);
conn = (HttpURLConnection) urlObj.openConnection();
conn.setDoOutput(false);
conn.setRequestMethod("GET");
conn.setRequestProperty("Accept-Charset", charset);
conn.setConnectTimeout(15000);
conn.connect();

} catch (IOException e) {
e.printStackTrace();
}

}

try {
//Receive the response from the server
InputStream in = new BufferedInputStream(conn.getInputStream());
BufferedReader reader = new BufferedReader(new InputStreamReader(in));
result = new StringBuilder();
String line;
while ((line = reader.readLine()) != null) {
result.append(line);
}

Log.d("JSON Parser", "result: " + result.toString());
} catch (IOException e) {
e.printStackTrace();
}

conn.disconnect();

// try parse the string to a JSON object
try {
System.out.println(jObj);
jObj = new JSONObject(result.toString());
} catch (JSONException e) {
Log.e("JSON Parser", "Error parsing data " + e.toString());
}

// return JSON Object
return jObj;
}

这是我每次提交数据时遇到的错误:

08-26 12:51:08.236 5089-5156/chtecnologies.myapplication D/JSON Parser: result:08-26 12:51:08.239 5089-5156/chtecnologies.myapplication E/JSON Parser: Error parsing data org.json.JSONException: End of input at character 0 of 08-26 12:51:08.793 5089-5096/chtecnologies.myapplication W/art: Suspending all threads took: 190.496ms 08-26 12:51:09.245 5089-5096/chtecnologies.myapplication W/art: Suspending all threads took: 137.277ms 08-26 12:51:09.267 5089-5156/chtecnologies.myapplication E/AndroidRuntime: FATAL EXCEPTION: AsyncTask #1 Process: chtecnologies.myapplication, PID: 5089 java.lang.RuntimeException: An error occured while executing doInBackground() at android.os.AsyncTask$3.done(AsyncTask.java:304) at java.util.concurrent.FutureTask.finishCompletion(FutureTask.java:355) at java.util.concurrent.FutureTask.setException(FutureTask.java:222) at java.util.concurrent.FutureTask.run(FutureTask.java:242) at android.os.AsyncTask$SerialExecutor$1.run(AsyncTask.java:231) at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1112) at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:587) at java.lang.Thread.run(Thread.java:818) Caused by: java.lang.NullPointerException: Attempt to invoke virtual method 'java.lang.String org.json.JSONObject.toString()' on a null object reference at chtecnologies.myapplication.PostPet$4$1.doInBackground(PostPet.java:154) at chtecnologies.myapplication.PostPet$4$1.doInBackground(PostPet.java:118) at android.os.AsyncTask$2.call(AsyncTask.java:292) at java.util.concurrent.FutureTask.run(FutureTask.java:237) at android.os.AsyncTask$SerialExecutor$1.run(AsyncTask.java:231)  at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1112)  at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:587)  at java.lang.Thread.run(Thread.java:818) 

数据成功进入数据库,但 JSONParser 似乎有问题,无法获取 PHP 文件的结果。

您能告诉我 JSONParser 文件或其他地方是否有问题吗?这是我第一次在我的应用程序中实现服务器,我希望你能帮助我!谢谢

最佳答案

您发送数据的方式看起来很可疑。如果您想在 POST 中发送数据,请使用 HttpURLConnection 就像

String postParam = "name=" + a + "&breed=" + BREED + "&type=" + "&images=" +
Whatever + "&description=" + c + "&coords=" + b;

try {
URL url = new URL(url);
HttpURLConnection connection = (HttpURLConnection) url.openConnection();

connection.setRequestMethod("POST");
connection.setDoOutput(true);
connection.setDoInput(true);
connection.setRequestProperty("Content-type", "application/x-www-form-urlencoded");

OutputStream os = connection.getOutputStream();
os.write(postParam.getBytes());
os.flush();
os.close();

// Fetching the response code
responseCode = connection.getResponseCode();
Log.d(TAG, "POST Response Code: " + responseCode);
} catch (Exception e) {
e.printStackTrace();
}

connection.setRequestMethod- 设置您想要使用 GET/POST 发送数据的方法

connection.setDoOutput(true)- 让您发送输出

connection.setDoInput(true)-让您在发送数据后接收输入(如果有)

希望这能解决您的问题!

关于java - 从服务器接收响应时出错?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/45897579/

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