Java n 数组中最年轻和最老的

Question

我编写了一个程序，根据我输入的年龄和姓名查找最年长和最年轻的人。问题是，程序只给了我最年长的人，最小的人的 else if 语句不执行。

public class Boo {

public static void main(String[] strings) {

  int[] age = new int[10];
  String[] name = new String[10];
  int count = 0;

  Scanner in = new Scanner(System.in);

  boolean notDone = true;

  int smallest = age[0];
  int largest = age[0];

  String smalName = "";
  String larName = "";


do {


  System.out.println("Enter name");
  name[count] = in.next();



  if (!name[count].equalsIgnoreCase("done")) {
    System.out.println("Enter age");
    age[count] = in.nextInt();

    if (age[count] > largest) {
      largest = age[count];
      larName = name[count];
    }
    else if (age[count] < smallest) {
      smallest = age[count];
      smalName = name[count];
    }

  }
  else if (name[count].equalsIgnoreCase("done")) {
    notDone = false;
  }

  count++;

}while(notDone && count < 3);

Answer 1

您的 smallest 变量将被实例化为 0，因为您将其设置为 age[0]，它是一个整数数组已经被初始化为默认值 0。

在您首次将年龄作为输入后，尝试将其设置为 age[0]，然后进行比较。

int smallest = age[0];
int largest = age[0];
do
{
  System.out.println("Enter name");
  name[count] = in.next();
  if (!name[count].equalsIgnoreCase("done"))
  {
    System.out.println("Enter age");
    age[count] = in.nextInt();

    if (count == 0)
    {
      smallest = age[0];
      largest = age[0];
      larName = name[0];
      smalName = name[0];
    }
    else
    {
      if (age[count] > largest)
      {
        largest = age[count];
        larName = name[count];
      }
      if (age[count] < smallest)
      {
        smallest = age[count];
        smalName = name[count];
      }
    }
  }
  else if (name[count].equalsIgnoreCase("done"))
  {
    notDone = false;
  }

  count++;

} while (notDone && count < 3);