java - 从文本文件读取时如何分割

Question

有点困惑

我有一个格式如下的文本文件

FooBoo，男，20,10/04/1988

例如，我知道如何拆分字符串

public loadData() {  

   String filepath = "G:\\Documents\\MEMove\\XXClients\\data.txt";

    BufferedReader bufReader = new BufferedReader(new FileReader(filepath));

    String line = bufReader.readLine();

    while (line != null) {

        // String[] parts = line.split("/");
        String[] parts = line.split(",");
        String part1 = parts[0];
        String part2 = parts[1];

        int part3 = Integer.parseInt(parts[3]);
        String [] sDOB = line.split("/");
        int sDOB1 = Integer.parseInt(sDOB[4]);
        People nPeople = new People(part1,part2,part3,sDOB1);

       readPeopleList.add(nPeople);
        line = bufReader.readLine(); 
    } //end of while 
    bufReader.close();

    for(People per: readPeopleList)
    {
        System.out.println("Reading.." + per.getFullName());

    }
}// end of method 

问题是我如何拆分 DOB/它不起作用，因为我收到 NumberFormatException 错误

任何想法

谢谢

Answer 1

首先，使用分隔符","分割行:

String line = "FooBoo,male,20,10/04/1988";
String[] parts = line.split(",");

然后，使用分隔符“\”分割最后一部分:

String dob = parts[parts.length - 1];
String[] sDob = dob.split("/");
for (String s : sDob) {
    System.out.println(s);
}

编辑:您可以将 sDob 转换为 ArrayList，如下所示:

ArrayList<String> sDobList = new ArrayList<>(Arrays.asList(sDob));