vba - 单独导出VBA程序(子/函数)

Question

在该项目中，我正在处理的所有代码都位于模块中，每个模块都有不同数量的过程。我正在尝试将 VBA 代码过程一一导出到以其各自模块命名的文件夹中。我已经有了导出整个模块的代码，但我喜欢这个挑战，并且以这种方式跟踪更改更有趣!

下面的导出代码适用于除自身之外的每个模块，因为我检查函数/子函数的开始和结束的方式。这实际上是一个循环问题，因为它认为检查中的短语是新子句的开始!

如果有人有一个更有创意的解决方案来标记在这里工作的函数或子函数的开始和结束，或者有办法调整我的，我将非常感激!

Sub ExportVBCode2()

    'NOTE: Globals will be included with the first procedure exported, not necessarily the procedure(s) they're used in

    Dim directory As String
    directory = "C:\Users\Public\Documents\VBA Exports" & "\"

    Dim fso As Object
    Set fso = CreateObject("scripting.filesystemobject")

'    If fso.FolderExists(Left(directory, Len(directory) - 1)) Then
'        fso.deletefolder Left(directory, Len(directory) - 1)
'    End If

    If Len(Dir(directory, vbDirectory)) = 0 Then
        MkDir directory
    End If

    Dim VBComponent As Object
    Dim Fileout As Object
    Dim i As Long

    Dim currLine As String
    Dim currLineLower As String
    Dim functionString As String

    Dim functionName As String
    Dim funcOrSub As String

    For Each VBComponent In ThisWorkbook.VBProject.VBComponents
        If VBComponent.Type = 1 Then    'Component Type 1 is "Module"

            If Len(Dir(directory & "\" & VBComponent.Name & "\", vbDirectory)) = 0 Then
                MkDir directory & VBComponent.Name
            End If

            For i = 1 To VBComponent.CodeModule.CountOfLines
                currLine = RTrim$(VBComponent.CodeModule.Lines(i, 1))
                currLineLower = LCase$(currLine)


                'TODO need a more clever solution for the if check below, because it catches ITSELF. Maybe regex ?

                If (InStr(currLineLower, "function ") > 0 Or InStr(currLineLower, "sub ") > 0) And InStr(currLineLower, "(") > 0 And InStr(currLineLower, ")") > 0 Then
                    'this is the start of a new function

                    Select Case InStr(currLineLower, "function ")
                        Case Is > 0
                            funcOrSub = "function"
                        Case Else
                            funcOrSub = "sub"
                    End Select

                    functionName = Mid(currLine, InStr(currLineLower, funcOrSub) + Len(funcOrSub & " "), InStr(currLine, "(") - InStr(currLineLower, funcOrSub) - Len(funcOrSub & " "))
                End If

                functionString = functionString & currLine & vbCrLf

                If Trim$(currLineLower) = "end sub" Or Trim$(currLineLower) = "end function" Then
                    'this is the end of a function

                    Set Fileout = fso.CreateTextFile(directory & "\" & VBComponent.Name & "\" & functionName & ".txt", True, True)

                    Fileout.Write functionString
                    Fileout.Close

                    functionString = ""
                    functionName = ""
                End If
            Next i

        End If
    Next VBComponent

End Sub

Answer 1

我认为问题的关键是检查该行包含术语“function”是否还包含函数名称后面的左括号。例如:私有(private)函数 foo(。因此，您希望计算 1 个空格字符，并且在下一个空格或逗号字符之前至少有 1 个左括号。