java - json.simple.JSONObject 无法使用 AWS Lambda JAVA 转换为 java.lang.String

Question

我正在尝试使用 Java Lambda 解析 POST 请求中的“正文”。我被这个错误困扰了一段时间。

 org.json.simple.JSONObject cannot be cast to java.lang.String

但是登录时的正文看起来像这样:

{"body":{"email":"test@test.com"}}

女巫应该与我正在做的解析一起工作，对吗？奇怪的是，插入在本地使用 JUNIT 运行，但在 AWS 上运行后无法在线运行。

@Override
public void handleRequest(InputStream inputStream, OutputStream outputStream, Context context) throws IOException {
    logger = context.getLogger();
    BufferedReader reader = new BufferedReader(new InputStreamReader(inputStream));
    Number user_id = null;
    String birthdate = null;
    List<Number> company_id = new ArrayList<Number>();
    String email = null;
    String employment_status = null;
    String firstname = null;
    String lastname = null;
    String login = null;
    String profile = null;
    List<Number> site_id = new ArrayList<Number>();
    String validation_status = null;
    JSONObject responseJson = new JSONObject();

    Map<String, AttributeValue> expressionAttributeValues = new HashMap<String, AttributeValue>();
    String filterExpression = "";
    String RegionAWS = REGION.toString();
    client = AmazonDynamoDBClientBuilder.standard().withRegion(RegionAWS).build();
    DynamoDB dynamoDB = new DynamoDB(client);
    Table table = dynamoDB.getTable("LI_user");
    try {
        JSONParser parser = new JSONParser();
        JSONObject event = (JSONObject) parser.parse(reader);
        logger.log(event.toJSONString());
        if (event.get("body") != null) {
            JSONObject bod = (JSONObject)parser.parse((String)event.get("body"));
         //   JSONObject bod = (JSONObject) event.get("body");
            if ( bod.get("id") != null) {
                user_id = (Number)bod.get("id");
            }
            if ( bod.get("birthdate") != null) {
                birthdate = (String)bod.get("birthdate");
            }
            if ( bod.get("email") != null) {
                email = (String) bod.get("email");
            }
            if ( bod.get("employment_status") != null) {
                employment_status = (String) bod.get("employment_status");
            }
            if ( bod.get("firstname") != null) {
                firstname = (String) bod.get("firstname");
            }
            if ( bod.get("lastname") != null) {
                lastname = (String) bod.get("lastname");
            }
            if ( bod.get("login") != null) {
                login = (String) bod.get("login");
            }
            if ( bod.get("profile") != null) {
                profile = (String) bod.get("profile");
            }
            if ( bod.get("validation_status") != null) {
                validation_status = (String) bod.get("validation_status");
            }
        }

Answer 1

替换

JSONObject bod = (JSONObject)parser.parse((String)event.get("body"));

与

JSONObject bod = (JSONObject)event.get("body");

if event 始终是 JSONObject 的实例(这似乎是理所当然的，否则您将在 JSONObject event = (JSONObject) parser.parse 处获得 ClassCast (读者)；)

您看到已记录

{"body":{"email":"test@test.com"}}

只是因为logger.log(event.toJSONString());