ruby-on-rails - rails : Creating a Multiple Model Form over n association levels

Question

谁能告诉我为什么这个问题末尾的表单不能正常工作？

• 保存不起作用
• 选择帮助程序不会选择根据对象@kid
的值

整个事情都是基于 Rails 2.2.2 的，不，升级到 Rails 2.3 来解决这个问题不是一个选择。 :-)

我用了this recipe构建多个模型表单。

# CLASS GRANDPARENT
class Grandparent < ActiveRecord::Base
  has_many :parents 
end

# CLASS PARENT
class Parent < ActiveRecord::Base
  belongs_to :grandparent, :class_name => "Grandparent", :foreign_key => "grandparent_id"
  has_many :kids
end

# CLASS KID
class Kid < ActiveRecord::Base
  belongs_to :parent, :class_name => "Parent", :foreign_key => "parent_id"

  # Virtual attribute setter for new self.parent.grandparent (Grandparent) attributes
  def new_grandparent_attributes=(_gp_attributes)
    self.parent.build_grandparent(_gp_attributes)
  end

  # Virtual attribute setter for existing self.parent.grandparent (Grandparent) attributes
  def existing_grandparent_attributes=(_gp_attributes)
    unless self.parent.grandparent.new_record?
      attributes = _gp_attributes[self.parent.grandparent.id.to_s]
      if attributes
        self.parent.grandparent.attributes = attributes
      else
        self.parent.grandparent.delete(grandparent)
      end
    end
  end

end

# CONTROLLER KIDS
class KidsController < ApplicationController
  def new
    @kid = Kid.new
  end

  def edit
    @kid = Kid.find(params[:id])
  end

  def create
    params[:kid][:new_grandparent_attributes] ||= {}
    @kid = Kid.new(params[:kid])
  end

  def update
    params[:kid][:existing_grandparent_attributes] ||= {}
    @kid = Kid.find(params[:id])
  end

end


# THIS IS THE MULTI-MODEL FORM USED IN THE VIEW

<% form_for(@kid) do |f| %>
    <p>
        <% new_or_existing = @kid.parent.grandparent.new_record? ? 'new' : 'existing' %>
        <% prefix = "kid[#{new_or_existing}_grandparent_attributes][]" %>

        <% fields_for prefix, @kid.parent.grandparent do |g_f| -%>
            <p>
              <%= g_f.label :, 'Grandparent Name' %><br />
              <!-- THE FOLLOWING FORM DOESN'T CHANGE ACCORDING TO EXISTING @child -->
              <%= @grandparents = Entity.find(:all, :order => :name)
                g_f.collection_select(:name ,@grandparents, :id, :name) 
                %>
            </p>
        <% end %>
    </p>
    <p>
        <%= f.label :name, "Kid Name" %><br />
        <%= f.text_field :name %>
    </p>
    <%= submit_tag 'Go' %>
<% end %>

Answer 1

好吧，如果我错了，请纠正我，但看起来您实际上并没有在任何地方保存该对象。在创建和更新操作中，您调用 new，然后不保存它。

要纠正这个问题，你可以这样做:

def create
  params[:kid][:new_grandparent_attributes] ||= {}
  @kid = Kid.new(params[:kid])
  if @kid.save
    # successful save logic here
  else
    #failed save logic here
  end
end

def update
  params[:kid][:existing_grandparent_attributes] ||= {}
  @kid = Kid.find(params[:id])
  if @kid.update_attributes(params[:kid])
    #successful save logic here
  else
    #failed save logic here
  end
end

然后，在您的选择框中，您尝试查找 Entity 的每条记录，而不是与 @kid 相关的 Entity 的那些字段。为此，您必须在 child 和祖 parent 之间建立关系。

# CLASS GRANDPARENT
class Grandparent < ActiveRecord::Base
  has_many :parents
  has_many :grand_kids, :through => :parents
end

# CLASS PARENT
class Parent < ActiveRecord::Base
  belongs_to :grandparent, :class_name => "Grandparent", :foreign_key => "grandparent_id"
  has_many :kids
end

# CLASS KID
class Kid < ActiveRecord::Base
  belongs_to :parent, :class_name => "Parent", :foreign_key => "parent_id"
  belongs_to :grandparent

  # ...

这样您就可以通过 @kid.grandparents 访问 child 的祖 parent 。然后您可以生成选择字段:

<%= g_f.collection_select(:name ,@kid.grandparents, :id, :name) %>