symfony - Symfony2 Controller 中的构造函数

Question

如何在 Symfony2 Controller 中定义构造函数。我想在 Controller 的所有方法中获取已登录的用户数据，目前我在 Controller 的每个操作中都执行类似的操作来获取已登录的用户。

$em = $this->getDoctrine()->getEntityManager("pp_userdata");
$user = $this->get("security.context")->getToken()->getUser();

我想在构造函数中执行一次，并使该登录用户可用于我的所有操作

Answer 1

对于在每个 Controller 操作之前执行代码的通用解决方案，您可以将事件监听器附加到 kernel.controller 事件，如下所示:

<service id="your_app.listener.before_controller" class="App\CoreBundle\EventListener\BeforeControllerListener" scope="request">
    <tag name="kernel.event_listener" event="kernel.controller" method="onKernelController"/>
    <argument type="service" id="security.context"/>
</service>

然后在您的 BeforeControllerListener 中，您将检查 Controller 以查看它是否实现了接口(interface)，如果实现了，您将从接口(interface)调用方法并传入安全上下文。

<?php

namespace App\CoreBundle\EventListener;

use Symfony\Component\HttpKernel\Event\FilterControllerEvent;
use Symfony\Component\Security\Core\SecurityContextInterface;
use App\CoreBundle\Model\InitializableControllerInterface;

/**
 * @author Matt Drollette <matt@drollette.com>
 */
class BeforeControllerListener
{

    protected $security_context;

    public function __construct(SecurityContextInterface $security_context)
    {
        $this->security_context = $security_context;
    }

    public function onKernelController(FilterControllerEvent $event)
    {
        $controller = $event->getController();

        if (!is_array($controller)) {
            // not a object but a different kind of callable. Do nothing
            return;
        }

        $controllerObject = $controller[0];

        // skip initializing for exceptions
        if ($controllerObject instanceof ExceptionController) {
            return;
        }

        if ($controllerObject instanceof InitializableControllerInterface) {
            // this method is the one that is part of the interface.
            $controllerObject->initialize($event->getRequest(), $this->security_context);
        }
    }
}

然后，任何您希望用户始终可用的 Controller 都只需实现该接口(interface)并设置用户，如下所示:

use App\CoreBundle\Model\InitializableControllerInterface;

class DefaultController implements InitializableControllerInterface
{
    /**
     * Current user.
     *
     * @var User
     */
    private $user;

    /**
     * {@inheritdoc}
     */
    public function initialize(Request $request, SecurityContextInterface $security_context)
    {
        $this->user = $security_context->getToken()->getUser();
    }
// ....
}

界面无非

namespace App\CoreBundle\Model;

use Symfony\Component\HttpFoundation\Request;
use Symfony\Component\Security\Core\SecurityContextInterface;

interface InitializableControllerInterface
{
    public function initialize(Request $request, SecurityContextInterface $security_context);
}