java - 在java递归中返回变量的更新值

Question

我想验证名称是否包含特殊字符。请让我知道这段代码有什么问题？我的代码是:

import java.util.Scanner;
import java.util.regex.Matcher;
import java.util.regex.Pattern;
public class Name {
    static Scanner in = new Scanner(System.in);

    public static String verifyName() {
        System.out.print("Enter your name: ");
        String name = in.nextLine();
        Pattern p = Pattern.compile("[a-zA-Z0-9]*");
        Matcher m = p.matcher(name);
        if(!m.matches()) {
            System.out.println("Invalid Name");
            verifyName();
        }
        return name;
    }

    public static void main(String args[]) {
        String result = verifyName();
        System.out.print(result);
    }
}

输出:

Enter your name: @li
Invalid Name
Enter your name: #sd
Invalid Name
Enter your name: Zain
@li

所需输出:

Enter your name: @li
Invalid Name
Enter your name: #sd
Invalid Name
Enter your name: Zain
Zain

提前致谢!

Answer 1

你的整个代码应该是这样的

import java.util.Scanner;
import java.util.regex.Matcher;
import java.util.regex.Pattern;

public class Name {
    static Scanner in = new Scanner(System.in);

    public static String verifyName() {
        System.out.print("Enter your name: ");
        String name = in.nextLine();
        Pattern p = Pattern.compile("[a-zA-Z0-9]*");
        Matcher m = p.matcher(name);
        if (!m.matches()) {
            System.out.println("Invalid Name");
            return verifyName();
        }
        return name;
    }

    public static void main(String args[]) {
        String result = verifyName();
        System.out.print(result);
    }
}

为了提高效率，您可以使用迭代循环。