python - 如何简化通过索引搜索列表项的过程？

Question

我有一个简单的程序:

pos = [1,2]
searched = [
    [1,3,4,6],
    [2,6,7,8],
    [0,1,2,8],
    [5,6,9,2]
]
print(searched[pos[0]][pos[1]])

7

现在我想要的是摆脱 searched[pos[0]][pos[1]] 的方法，只需键入 searched[[pos]].

有没有办法做到这一点，或者我每次都必须写下来

I have gotten a lot of suggestions, but what I am searching for is a way to do this in one neat line, simplifying everything.
That means that things like using a function, converting to a specific dictionary or even enumerate don't work for me, so for anyone looking at this post later:
.
I suggest using np.array(variable) while defining said variable so you can use variable[pos]

Answer 1

不知道你是否可以接受，但一个函数就可以了:

def search_for_list_item_by_index(a_list, row, col):
    return a_list[row][col]

print(search_for_list_item_by_index(searched, 1, 2))

这将按预期打印 7。