java - Spring Security - 405请求方法 'POST'不支持

Question

我已经在我的项目中实现了 Spring Security，但是当我尝试登录时，我收到状态 405。我已经在 form 中添加了 csrf token 。

这是我发送用户名和密码时收到的错误:HTTP 状态 405 - 不支持请求方法“POST”

Spring 版本:4.0.2.RELEASED

<div class="login-form">
    <c:url var="loginUrl" value="/login" />
    <form action="${loginUrl}" method="post" class="form-horizontal">
        <c:if test="${param.error != null}">
            <div class="alert alert-danger">
                <p>Invalid username and password.</p>
            </div>
        </c:if>
        <c:if test="${param.logout != null}">
            <div class="alert alert-success">
                <p>You have been logged out successfully.</p>
            </div>
        </c:if>
        <div class="input-group input-sm">
            <label class="input-group-addon" for="username">
                <i class="fa fa-user"></i>
            </label>
            <input type="text" class="form-control" id="username"
                name="clientusername" placeholder="Enter Username" required>
        </div>
        <div class="input-group input-sm">
            <label class="input-group-addon" for="password">
                <i class="fa fa-lock"></i>
            </label>
            <input type="password" class="form-control" id="password"
                name="clientpassword" placeholder="Enter Password" required>
        </div>

        <input type="hidden" name="${_csrf.parameterName}"
            value="${_csrf.token}" />

        <div class="form-actions">
            <input type="submit" class="btn btn-block btn-primary btn-default"
                value="Log in">
        </div>
    </form>
</div>

安全配置:

@Configuration
@EnableWebSecurity
public class SecurityConfiguration extends WebSecurityConfigurerAdapter {

    @Autowired
    @Qualifier("G2BUserDetailsService")
    UserDetailsService userDetailsService;

    @Autowired
    public void configureGlobalSecurity(AuthenticationManagerBuilder auth) throws Exception {
        auth.userDetailsService(userDetailsService);
    }

    @Override
    protected void configure(HttpSecurity http) throws Exception {
      http.authorizeRequests()
        .antMatchers("/", "/home").permitAll()
        .antMatchers("/admin/**").access("hasRole('ADMIN')")
        .and().formLogin().loginPage("/login")
        .usernameParameter("clientusername").passwordParameter("clientpassword")
        .and().csrf()
        .and().exceptionHandling().accessDeniedPage("/Access_Denied");
//        .and().csrf().disable();
    }

Controller :

@RequestMapping(value = "/login", method = RequestMethod.GET)
public ModelAndView loginPage() {
    return new ModelAndView("login");
}

@RequestMapping(value="/logout", method = RequestMethod.GET)
public String logoutPage (HttpServletRequest request, HttpServletResponse response) {
    Authentication auth = SecurityContextHolder.getContext().getAuthentication();
    if (auth != null){    
        new SecurityContextLogoutHandler().logout(request, response, auth);
    }
    return "redirect:/login?logout";
}

 @RequestMapping(value = "/Access_Denied", method = RequestMethod.GET)
    public ModelAndView accessDeniedPage(ModelMap model) {
        model.addAttribute("user", getPrincipal());
        return new ModelAndView("accessDenied");
    }

 @RequestMapping(value = "/admin", method = RequestMethod.GET)
    public ModelAndView adminPage(ModelMap model) {
        model.addAttribute("user", getPrincipal());
        return new ModelAndView("admin");
    }

 private String getPrincipal(){
        String userName = null;
        Object principal = SecurityContextHolder.getContext().getAuthentication().getPrincipal();

        if (principal instanceof UserDetails) {
            userName = ((UserDetails)principal).getUsername();
        } else {
            userName = principal.toString();
        }
        return userName;
    }

几乎每个有关此问题的主题都说我们需要添加 csrf token ，但我已经添加了。我错过了什么吗？

Answer 1

首先csrf是enabled by default从 Spring 4.0 开始，它已在 Spring 中使用，因此无需自己显式启用它。

其次，没有端点可供您验证登录身份。您正在做的是将请求发送到 /login ，该请求仅接受 GET 请求。您可以创建另一个 Controller 方法来接收 POST 请求并进行身份验证，或者您可以使用 UserDetailsS​​ervice。

安全配置

protected void configure(HttpSecurity http) throws Exception {
        http
                .authorizeRequests()
                    .antMatchers("/login-form")
                        .anonymous()
                    .and()
                .formLogin()
                    .loginPage("/user-login") 
                    .defaultSuccessUrl("/admin", true) // the second parameter is for enforcing this url always
                    .loginProcessingUrl("/login")
                    .failureUrl("/user-login")
                    .permitAll();
}

@Autowired 
private UserDetailsService userDetailsService;  

@Autowired
public void configureGlobal(AuthenticationManagerBuilder auth) throws Exception {
    BCryptPasswordEncoder pe = new  BCryptPasswordEncoder();
    auth.userDetailsService(userDetailsService).passwordEncoder(pe);
}

这里我们的 View 页面是 /user-login ，处理 URL 是 /login 这意味着在您的 Controller 中，您需要删除 /login< 的映射 并添加以下内容:

Controller

@RequestMapping(value="/user-login", method=RequestMethod.GET)
public ModelAndView loginForm() {
    return new ModelAndView("login-form");
}

并改变你的观点。

查看(login-form.jsp)

<c:url value="/login" var="loginUrl"/>
<form action="${loginUrl}" method="post" modelAttribute="user">
    Username: <input type="text" id="username" name="username" placeholder=""><br>
    Password: <input type="password" id="password" name="password" placeholder=""><br>

    <input type="hidden"
    name="${_csrf.parameterName}"
    value="${_csrf.token}"/>
    <button type="submit">Login</button>
</form>