java - 使用 ShareCompat 共享内容

Question

当我尝试使用 ShareCompat 共享 my_file.html 时，遇到一个奇怪的问题。作为最佳实践，我创建了自己的 FileProvider，但收到错误 java.lang.IllegalArgumentException: 无法找到包含/forms/Proof_of_Life_Form.html 的配置根 我想我已经设置了所有内容正确。

我的 XML 我已经为此创建了一个提供程序。

<provider
        android:name="android.support.v4.content.FileProvider"
        android:authorities="com.douglas.sample"
        android:exported="false"
        android:grantUriPermissions="true">
        <meta-data
            android:name="android.support.FILE_PROVIDER_PATHS"
            android:resource="@xml/filepaths" />
</provider>

这是我在 res/xml/filepaths 中创建的 filepath

<?xml version="1.0" encoding="utf-8"?>
    <paths>
        <cache-path path="/forms" name="forms" />
    </paths>

还有我负责调用共享内容的方法。

    public void shareContent() {
            File file = new File("/forms/", fileName + ".html");
            Uri uri = FileProvider.getUriForFile(getContext(), "com.douglas.sample", file);
            Intent shareIntent = ShareCompat.IntentBuilder.from(getActivity())
                    .setType(getActivity().getContentResolver().getType(uri))
                    .setStream(uri)
                    .getIntent();
            //Provide read access
            shareIntent.setData(uri);
            shareIntent.addFlags(Intent.FLAG_GRANT_READ_URI_PERMISSION);
            startActivity(Intent.createChooser(shareIntent, getString(R.string.share_form)));
        }

最后我的异常(exception):

java.lang.IllegalArgumentException: Failed to find configured root that contains /forms/Proof_of_Life_Form.html
                                                                                at android.support.v4.content.FileProvider$SimplePathStrategy.getUriForFile(FileProvider.java:719)
                                                                                at android.support.v4.content.FileProvider.getUriForFile(FileProvider.java:404)
                                                                                at com.douglas.sample.TabbedFormsFragment$2.run(TabbedFormsFragment.java:254)
                                                                                at android.os.Handler.handleCallback(Handler.java:751)
                                                                                at android.os.Handler.dispatchMessage(Handler.java:95)
                                                                                at android.os.Looper.loop(Looper.java:154)
                                                                                at android.app.ActivityThread.main(ActivityThread.java:6682)
                                                                                at java.lang.reflect.Method.invoke(Native Method)
                                                                                at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:1520)
                                                                                at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:1410)

有什么想法吗？谢谢:D

Answer 1

您的代码中似乎存在一些小错误。

尝试以下操作:

    <provider
        android:name="android.support.v4.content.FileProvider"
        android:authorities="${applicationId}.FileProvider"
        android:exported="false"
        android:grantUriPermissions="true">
        <meta-data
            android:name="android.support.FILE_PROVIDER_PATHS"
            android:resource="@xml/provider_paths"/>
    </provider>

然后在您的provider_paths.xml中尝试:

<?xml version="1.0" encoding="utf-8"?>
<paths>
<!-- We would like to give access to the External Storage of the app.
     external_files will expose the path app to storage/emulated/0/ and the
     "." is to actually point the root folder. The final path of the Uri will start
     from path above and whatever folder we defined. For application upgrades
     will be external_files/Android/data/package name/files/updates/name of update apk.-->
<external-path
    name="external_files"
    path="."/>
</paths>

然后无论你想在哪里使用它，请尝试:

String path = Uri.parse(your_file_uri).getPath();
FileProvider.getUriForFile(application, PROVIDER, new File(path)),my_file_type);

其中 my_file_type = 例如.apk 文件的“application/vnd.android.package-archive”

希望对你有帮助!!!