java - 为什么java中不能连续输入两个字符串？

Question

我的程序在输入一个字符串后终止。它不需要字符串 2 输入。

这是代码片段:

    public static void main (String[] args) {
        Scanner scn= new Scanner(System.in);
        int T ;
        T=scn.nextInt();
        while(T!=0){
            String s1 = scn.nextLine(); // after i give input for the first string ,program terminates!
            String s2 = scn.nextLine(); // program terminates before asking for s2 input
            System.out.println(isMetaString(s1,s2));
            T--;
        }
    }

Answer 1

public static void main (String[] args) {
    Scanner scn= new Scanner(System.in);
    int T ;
    T=scn.nextInt();

    // scn.nextLine();  // for enter.
    // here after entering int value, 
    // you must be pressing enter,
    // that 'enter' is getting stored in s1,
    // and then when you give first string it is getting stored in s2 
    // and that is why your program is terminating.

    while(T!=0){
        String s1 = scn.nextLine(); // after i give input for the first string ,program terminates!
        String s2 = scn.nextLine(); // program terminates before asking for s2 input
        System.out.println(isMetaString(s1,s2));
        T--;
    }
}

解决方案:在 sca.nextInt() 之后添加 sca.nextLine() 即可。将解决问题