list - 如何在 Kotlin 中将项目添加到列表中？

Question

我正在尝试将元素列表添加到字符串列表中，但我发现 Kotlin没有像 java 这样的添加功能所以请帮助我如何将项目添加到列表中。

class RetrofitKotlin : AppCompatActivity() {

    var listofVechile:List<Message>?=null
    var listofVechileName:List<String>?=null
    var listview:ListView?=null
    var progressBar:ProgressBar?=null
    override fun onCreate(savedInstanceState: Bundle?) {
        super.onCreate(savedInstanceState)
        setContentView(R.layout.activity_retrofit_kotlin)

        listview=findViewById<ListView>(R.id.mlist)
        var apiInterfacee=ApiClass.client.create(ApiInterfacee::class.java)
        val call=apiInterfacee.getTaxiType()
        call.enqueue(object : Callback<TaxiTypeResponse> {

            override fun onResponse(call: Call<TaxiTypeResponse>, response: Response<TaxiTypeResponse>) {

                listofVechile=response.body()?.message!!
                println("Sixze is here listofVechile   ${listofVechile!!.size}")
                if (listofVechile!=null) {
                    for (i in 0..listofVechile!!.size-1) {

                        //how to add the name only listofVechileName list

                    }
                }
                //println("Sixze is here ${listofVechileName!!.size}")
                val arrayadapter=ArrayAdapter<String>(this@RetrofitKotlin,android.R.layout.simple_expandable_list_item_1,listofVechileName)
                listview!!.adapter=arrayadapter

            }
            override fun onFailure(call: Call<TaxiTypeResponse>, t: Throwable) {

            }
        })
    }
}

Answer 1

更惯用的方法是使用 MutableList而不是专门 ArrayList .您可以声明:

val listOfVehicleNames: MutableList<String> = mutableListOf()

并以这种方式添加它。或者，您可能希望更喜欢不变性，并将其声明为:

var listOfVehicleNames: List<String> = emptyList()

在您的完成块中，只需重新分配它:

listOfVehicleNames = response.body()?.message()?.orEmpty()
    .map { it.name() /* assumes name() function exists */ }