react-native - TypeError : props. navigation.getParam 不是函数。在( Prop .navigation.getParam ('name')

Question

我在 TypeError : props.navigation.getParam 上遇到问题不是函数。在 (props.navigation.getParam('name') .我正在使用 reactNavigation version 5.x.此代码适用于 reactNavigation 3 .我究竟做错了什么？
这是我的代码

export default class ChatScreen extends Component {
static navigationOption = ({ navigation }) => {
    return {
        title: navigation.getParam('name', null)
    }
}
 
constructor(props) {
    super(props);
   
  
    this.state = {
        person:{
           name:props.navigation.getParam('name'),
            phone:props.navigation.getParam('phone'),
            // name:'Raushan',
          //   phone:9931428888
        },
        textMessage: ''
    };
   
}

状态部分值错误。
堆栈导航器
`

const Stack = createStackNavigator();
function App() {
  return (
    <NavigationContainer>
      <Stack.Navigator initialRouteName="Auth">
        <Stack.Screen name="AuthLoading" component={AuthLoadingScreen} />
        <Stack.Screen name="App" component={HomeScreen} options={{ title: 'Chats' }}/>
        <Stack.Screen name="Chat" component={ChatScreen} options={({ route }) => ({ title: route.params.name })}/>
        <Stack.Screen name="Auth" component={LoginScreen} />
      </Stack.Navigator>
    </NavigationContainer>
  );
}
export default App;

`
和导航屏幕 onPress={()=>this.props.navigation.navigate('Chat',item)}

Answer 1

使用 props.route.params.name 这是工作

 this.state = {
    person:{
      name: props.route.params.name,
      phone: props.route.params.phone,
    },
    textMessage: ''
};