regex - 用 标签内的方括号 (<>) 替换除 标签内的换行符

Question

我使用 question 中提供的答案替换了 pre 标签外的所有换行符.

\n(?![^<]*<\/pre>)

它工作正常，直到 pre 标签中的内容有 < 或 > 括号。

例如，输入:

<p>Test contennt for regex
with line breaks</p>
<pre>code block 
with multi line content
working fine</pre>
<pre class="brush:C#">
test line break before 
open paranthesis < is not working fine
line breaks after paranthesis
is accepted
</pre>

输出是

<p>Test contennt for regexwith line breaks</p><pre>code block 
with multi line content
working fine</pre><pre class="brush:C#">test line break before open paranthesis < is not working fine
line breaks after paranthesis
is accepted
</pre>

这是不正确的 - 并非所有换行符都被删除。

见 this regex101 .

Answer 1

尝试这个:

/\n(?=((?!<\/pre).)*?(<pre|$))/sg

这个想法是有一个大的前瞻性。这

((?!<\/pre).)*?

重复匹配任何字符(包括带有 . 的换行符)，并且其后跟

(<pre|$)

要求上述字符不是 <在 </pre .然后，匹配 <pre (表示原始换行符不在 <pre 内，或与文件末尾匹配。

https://regex101.com/r/cjZQO9/2

随着输入

<p>Test contennt for regex
with line breaks</p>
<pre>code block 
with multi line content
working fine</pre>
text
more text
<pre class="brush:C#">
test line break before 
open paranthesis < is not working fine
line breaks after paranthesis
is accepted
</pre>
text

输出是

<p>Test contennt for regexwith line breaks</p><pre>code block 
with multi line content
working fine</pre>textmore text<pre class="brush:C#">
test line break before 
open paranthesis < is not working fine
line breaks after paranthesis
is accepted
</pre>text