msbuild任务读取dll的AssemblyFileVersion

Question

我需要读取 dll 的 AssemblyFileVersion 而不仅仅是 Version。我尝试过:

<Target Name="RetrieveIdentities">
    <GetAssemblyIdentity AssemblyFiles="some.dll">
        <Output
            TaskParameter="Assemblies"
            ItemName="MyAssemblyIdentities"/>
    </GetAssemblyIdentity>
    <Message Text="%(MyAssemblyIdentities.FileVersion)" />
</Target>

脚本运行但不输出任何内容。如果我将 FileVersion 更改为 Version，它会正确输出 AssemblyVersion。如何使用我的脚本获取 AssemblyFileVersion？

Answer 1

借用this answer ，我能够创建自定义 MSBuild 任务:

<UsingTask
  TaskName="GetFileVersion"
  TaskFactory="CodeTaskFactory"
  AssemblyFile="$(MSBuildToolsPath)\Microsoft.Build.Tasks.v4.0.dll">

  <ParameterGroup>
    <AssemblyPath ParameterType="System.String" Required="true" />
    <Version ParameterType="System.String" Output="true" />
  </ParameterGroup>
  <Task>
    <Using Namespace="System.Diagnostics" />
    <Code Type="Fragment" Language="cs">
      <![CDATA[
      Log.LogMessage("Getting version details of assembly at: " + this.AssemblyPath, MessageImportance.High);

      this.Version = FileVersionInfo.GetVersionInfo(this.AssemblyPath).FileVersion;  
    ]]>
    </Code>
  </Task>
</UsingTask>

然后从目标内部消耗它:

<GetFileVersion AssemblyPath="some.dll">
  <Output TaskParameter="Version" PropertyName="MyAssemblyFileVersion" />
</GetFileVersion>
<Message Text="File version is $(MyAssemblyFileVersion)" />