c++ - C++中的“' yc ' can not be used as a function”错误

Question

我正在使用C++计算NACA 4位机翼坐标。在这段代码中，我使用了 Armadillo 库的linspace函数将x划分为线性间隔的点。当我使用for循环为每个yc的值计算x的值时，出现错误“yc”不能用作函数。感谢您的帮助。

#include<iostream>
#include<armadillo>
#include<vector>

using namespace std;
using namespace arma;
int main()
{

    float a[3];
    float c;
    int gp = 100;

    cout << "Please Enter NACA 4 digits" << endl;
    cout << "Please Enter 1st digit" << endl;
    cin >> a[0] ;
    cout << "Please Enter 2nd digit" << endl;
    cin >> a[1] ;
    cout << "Please Enter last 2 digits" << endl;
    cin >> a[2] ;
    cout << "Please Enter Chord Length" << endl;
    cin >> c;

    float m=(a[0]*c)/100;
    float p=(a[1]*c)/10;
    float t=(a[2]*c)/100;

    cout << m << endl;
    cout << p << endl;
    cout << t << endl;
    vec x = linspace<vec>(0, c, gp);
    float yc;
    for(int i=0;i<gp;++i)

        {
            if (x(i) = 0 && x(i) <= p){
            yc(i) = (m/(p*p))*((2*p*(x(i)))-(x(i)*x(i)));
        }
            if (x(i) > p && x(i) <= c) {
            yc(i) =(m/((1-p)*(1-p)))*((1-(2*p))+(2*p*x(i))-(x(i)*x(i)));
        }
        }
    cout<< yc <<endl;
return 0;
}

Answer 1

yc是单个浮点数。

编译器将symbol( )视为函数调用。这就是错误的含义。

也许创建一个yc数组

float yc[gp];

和使用

yc[i] = ....

如突出显示- yc[gp]可能不起作用，因此

float * yc = new float[gp];

并在 main()的末尾

delete []yc;