java - 无法在 selenium-java 中使用 xpath 错误定位元素

Question

这是我要执行的代码

public WebDriver createPart() {

    try {
        driver.findElement(By.id("username")).sendKeys("502409373");
        driver.findElement(By.id("password")).sendKeys("Magic14Magic");
        driver.findElement(By.id("submitFrmShared")).click();
        driver.manage().timeouts().implicitlyWait(70, TimeUnit.SECONDS);
        driver.manage().timeouts().pageLoadTimeout(70, TimeUnit.SECONDS);
        Select dropCountry = new Select(driver.findElement(By.id("txtNewLocation")));
        dropCountry.selectByVisibleText("India");
        driver.manage().timeouts().implicitlyWait(50, TimeUnit.SECONDS);
        driver.findElement(By.xpath("//button[@class='btn']/label")).click();
        driver.manage().timeouts().implicitlyWait(70, TimeUnit.SECONDS);
        driver.manage().timeouts().pageLoadTimeout(70, TimeUnit.SECONDS);
        Thread.sleep(10000);
        driver.findElement(By.xpath("//li[@class='icon-button add']/span")).click();
        driver.findElement(By.xpath("//div[@id='ENCActions']/a/label")).click();    
        driver.findElement(By.xpath("//label[starts-with(text(),'Create Part...')]")).click();
        driver.manage().timeouts().implicitlyWait(70, TimeUnit.SECONDS);
        driver.manage().timeouts().pageLoadTimeout(70, TimeUnit.SECONDS);
        String parentWindowHandler = driver.getWindowHandle(); // Store your parent window
        String subWindowHandler = null; 
        Set<String> handles = driver.getWindowHandles(); // get all window handles
        Iterator<String> iterator = handles.iterator();
        while (iterator.hasNext()){
            subWindowHandler = iterator.next();
        }
        driver.switchTo().window(subWindowHandler); // switch to popup window
        WebDriverWait wait = new WebDriverWait(driver, 10);
        WebElement element = driver.findElement(By.xpath("//select[@id='Type-Field']//following-sibling::div//div//input"));
        element.click();
        Thread.sleep(3000);
        element.sendKeys(Keys.BACK_SPACE);
        Thread.sleep(3000);
        element.sendKeys("Subassy");
        Thread.sleep(4000);
        driver.findElement(By.xpath("//div[@data-value='Subassy']")).click();
        driver.findElement(By.xpath("//span[text()='Description']//parent::td//following-sibling::td//textarea")).sendKeys("Testing");
        driver.findElement(By.xpath("//option[text()='BioSc-DS-Chemical']//parent::select")).click();
        Thread.sleep(2000);
        driver.findElement(By.xpath("//option[text()='BioSc-DS-Chemical']")).click();
        driver.findElement(By.xpath("//a[text()='Done']")).click();
        driver.switchTo().window(parentWindowHandler);
        driver.manage().timeouts().implicitlyWait(70, TimeUnit.SECONDS);
        driver.manage().timeouts().pageLoadTimeout(70, TimeUnit.SECONDS);
        wait = new WebDriverWait(driver, 60);
        element = wait.until(ExpectedConditions.elementToBeClickable(By.xpath("//a[@title='Part Details']")));
        element.click();

    } catch (InterruptedException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }
    return driver;

}

这是该元素的html代码，我找不到。

<div class="tabcontent">
<a class="tablink" href="javascript:void(0);" title="Part Details" 
onclick="tvcTabPage_tabClicked(this,true)">Part Details</a>
<a href="javascript:void(0);" class="closetab" 
onclick="tvcTabPage_tabClosed(this)" title="Close Tab"></a>
</div>

这是堆栈跟踪

Exception in thread "main" org.openqa.selenium.TimeoutException: Expected 
condition failed: waiting for element to be clickable: By.xpath: 
//a[@title='Part Details'] (tried for 60 second(s) with 500 MILLISECONDS 
interval)

Caused by: org.openqa.selenium.NoSuchElementException: Cannot locate an 
element using By.xpath: //a[@title='Part Details']

尽管我已经使用了等待语句。我无法找到该元素。我已经使用 chrome xpath 验证了 xpath。请帮助我解决我的问题。 Selenium 版本:3.3.1。实际流程是，我单击主页中的链接，结果是一个包含表单的弹出窗口。填写表格并单击“完成”后，弹出窗口会自动关闭，主页会刷新并打开一个新页面。现在，我尝试单击新主页中的“零件详细信息”链接，但该链接不起作用。

我添加了这段代码来查找正确的窗口处理程序。

subWindowHandler = null;
        Set<String> handles1 = driver.getWindowHandles(); // get all window handles
        iterator = handles1.iterator();
        while (iterator.hasNext()){
            subWindowHandler = iterator.next();
            driver.switchTo().window(subWindowHandler);
            element =  wait.until(ExpectedConditions.visibilityOfElementLocated(By.xpath("//a[@title='Part Details']")));
            System.out.println("KK1");
        }

给我输出:

Exception in thread "main" org.openqa.selenium.TimeoutException: Expected 
condition failed: waiting for visibility of element located by By.xpath: 
//a[@title='Part Details'] (tried for 10 second(s) with 500 MILLISECONDS 
interval)

这里，所需的“零件详细信息”元素位于我已包含在代码中的框架中。但是，我无法在框架内找到该元素。这是我修改后的代码。

System.out.println(driver.switchTo().window(parentWindowHandler).getTitle());           
        driver.switchTo().frame("content");         
        driver.switchTo().frame("detailsDisplay");          
        driver.findElement(By.xpath("//a[@title='Part Details']")).click(); 

但是我遇到了这个错误。

Exception in thread "main" org.openqa.selenium.NoSuchElementException: no 
such element: Unable to locate element: 
{"method":"xpath","selector":"//a[@title='Part Details']"}

我附上了 html 代码的屏幕截图。 HTML screenshot

Answer 1

更改 visibilityOfElementLocated 而不是 elementToBeClickable。你可以直接找到webeelement，然后点击它，如下图:

element = wait.until(ExpectedConditions.visibilityOfElementLocated(By.xpath("//a[@title='Part Details']")));